欧拉项目 #8 题目要求找出一个特定长度的连续数字中,乘积最大的一组数字。下面是一个使用Python解决该问题的示例代码:
def find_largest_product(num_string, length):
max_product = 0
for i in range(len(num_string) - length + 1):
product = 1
for j in range(i, i + length):
product *= int(num_string[j])
if product > max_product:
max_product = product
return max_product
if __name__ == "__main__":
num_string = "73167176531330624919225119674426574742355349194934" \
"96983520312774506326239578318016984801869478851843" \
"85861560789112949495459501737958331952853208805511" \
"12540698747158523863050715693290963295227443043557" \
"66896648950445244523161731856403098711121722383113" \
"62229893423380308135336276614282806444486645238749" \
"30358907296290491560440772390713810515859307960866" \
"70172427121883998797908792274921901699720888093776" \
"65727333001053367881220235421809751254540594752243" \
"52584907711670556013604839586446706324415722155397" \
"53697817977846174064955149290862569321978468622482" \
"83972241375657056057490261407972968652414535100474" \
"82166370484403199890008895243450658541227588666881" \
"16427171479924442928230863465674813919123162824586" \
"17866458359124566529476545682848912883142607690042" \
"24219022671055626321111109370544217506941658960408" \
"07198403850962455444362981230987879927244284909188" \
"84580156166097919133875499200524063689912560717606" \
"05886116467109405077541002256983155200055935729725" \
"71636269561882670428252483600823257530420752963450"
length = 13
largest_product = find_largest_product(num_string, length)
print(f"The largest product of {length} adjacent digits is: {largest_product}")
这段代码首先定义了一个find_largest_product
函数,它接受一个数字字符串和一个长度参数。函数使用两个嵌套的循环来计算每个连续数字乘积的最大值,并返回该最大值。
在main
函数中,我们定义了给定的数字字符串和长度,并调用find_largest_product
函数来找到最大乘积。最后,打印出结果。
请确保将题目描述的数字字符串和长度传递给find_largest_product
函数,并根据需要进行修改。