X-11方法在R中的季节性分量不一致性问题

在R中，可以使用forecast包中的stlf函数解决X-11方法在季节性分量不一致性问题。下面是一个示例代码：

# 导入forecast包
library(forecast)

# 读取时间序列数据
data <- ts(c(27, 35, 42, 52, 63, 75, 86, 94, 105, 117, 131, 142, 153, 164, 174, 185, 196, 207, 218, 227, 238, 249, 258, 268, 276, 287, 297, 307, 317, 326, 336, 346, 357, 367, 376, 386, 395, 404, 413, 421, 429, 438, 446, 454, 462, 469, 476, 483, 490, 496, 503, 509, 515, 521, 527, 532, 537, 541, 546, 551, 556, 561, 566, 571, 576, 581, 586, 592, 598, 605, 611, 618, 624, 631, 639, 647, 655, 662, 670, 678, 685, 692, 699, 706, 713, 720, 727, 735, 743, 751, 759, 767, 775, 784, 792, 800, 808, 816, 824, 832, 840, 848, 856, 864, 872, 880, 888, 896, 904, 912, 920, 928, 936, 944, 952, 960, 968, 976, 984, 992, 1000, 1008, 1016, 1024, 1032, 1040, 1048, 1056, 1064, 1072, 1080, 1088, 1096, 1104, 1112, 1120, 1128, 1136, 1144, 1152, 1160, 1168, 1176, 1184, 1192, 1200, 1208, 1216, 1224, 1232, 1240, 1248, 1256, 1264, 1272, 1280, 1288, 1296, 1304, 1312, 1320, 1328, 1336, 1344, 1352, 1360, 1368, 1376, 1384, 1392, 1400, 1408, 1416, 1424, 1432, 1440, 1448, 1456, 1464, 1472, 1480, 1488, 1496, 1504, 1512, 1520, 1528, 1536, 1544, 1552, 1560, 1568, 1576, 1584, 1592, 1600, 1608, 1616, 1624, 1632, 1640, 1648, 1656, 1664, 1672, 1680, 1688, 1696, 1704, 1712, 1720, 1728, 1736, 1744, 1752, 1760, 1768, 1776, 1784, 1792, 1800, 1808, 1816, 1824, 1832, 1840, 1848, 1856, 1864, 1872, 1880, 1888, 1896, 1904, 1912, 1920, 1928, 1936, 1944, 1952, 1960, 1968, 1976, 1984, 1992, 2000, 2008, 2016, 2024, 2032, 2040, 2048, 2056, 2064, 2072, 2080, 2088, 2096, 2104, 2112, 2120, 212