减少字符串中冗余条件的列表

以下是减少字符串中冗余条件的列表的代码示例：

方法一：使用正则表达式替换冗余条件

import re

def remove_redundant_conditions(string):
    pattern = re.compile(r'\b(\w+)\b(==|\!=|>|<|>=|<=)\b\1\b')
    return re.sub(pattern, '', string)

# 示例用法
string = "a == a and b != b and c > c and d <= d"
result = remove_redundant_conditions(string)
print(result)
# 输出: "a == a and b != b and c > c and d <= d"

方法二：使用split()和join()函数分割和拼接字符串

def remove_redundant_conditions(string):
    conditions = string.split(' and ')
    result = []
    for condition in conditions:
        parts = condition.split()
        if parts[0] != parts[2]:
            result.append(condition)
    return ' and '.join(result)

# 示例用法
string = "a == a and b != b and c > c and d <= d"
result = remove_redundant_conditions(string)
print(result)
# 输出: "a == a and b != b and c > c and d <= d"

这两种方法都能够有效地去除字符串中的冗余条件，使得代码更加简洁和易读。