Hey there! Let's unpack this error step by step so you understand exactly what's going on.

First, let's break down the core meaning of the error:
In Python, assignment statements work by storing a value in a "container"—a variable name that points to a spot in memory. A "literal" is a fixed value like 10, "hello", or True—it's not a container, it's the value itself. You can't assign something to a literal because there's no place to store the new value; it's just a static piece of data. Think of it like trying to pour water into a rock—there's no space to hold it!

Now, why does your code x=10, y=20 trigger this error?
Python's syntax rules are strict about how it reads statements. When you write this line without a semicolon or proper structure, Python doesn't interpret it as two separate assignments. Instead, it gets confused about what you're trying to target for assignment, and ends up misparsing the line as an attempt to assign a value to a literal (like 10), which is impossible—hence the error.

The Fixes (and Why They Work) #

You already found the right solutions, but let's clarify why each one works:

• Split into two lines:

  x = 10
  y = 20
  

  This is the clearest approach. Python sees each line as a separate assignment statement, assigning 10 to x and 20 to y without any confusion.
• Use a semicolon for one-line multiple assignments:

  x = 10; y = 20
  

  The semicolon tells Python, "Hey, this is two separate statements in one line." It behaves exactly like splitting into two lines, just condensed.
• Tuple unpacking (multiple assignment):

  x, y = 10, 20
  

  Here, Python recognizes the left side as a list of variables and the right side as a tuple of values (it automatically adds parentheses around 10, 20). It then matches each variable to the corresponding value—x gets 10, y gets 20. This is a clean, Pythonic way to assign multiple values in one line.

Quick Recap #

The "can't assign to literal" error is Python's way of saying: "You're trying to put a value into something that isn't a storage container (like a variable)." Your original line tripped up the parser because it didn't follow Python's assignment syntax rules. Adjusting the structure to clearly indicate you're assigning to variables fixes the problem.

内容的提问来源于stack exchange，提问作者asdfg