Got it, let's figure out why your regex isn't working and fix this step by step.

Why Your Current Code Fails #

The regex /
/gmi you're using is targeting an invisible control character (not ¶ or ∂), so it can't find the symbols you care about. Those � symbols you see are just display issues from encoding mismatches, but the actual underlying characters are still ¶ (Unicode U+00B6) and ∂ (Unicode U+2202).

Solution 1: Match Using Unicode Escape Sequences (Most Reliable) #

To avoid encoding-related problems, use the Unicode escape codes for each symbol in your regex. This works consistently across environments.

Example: Find the Symbols

const value = 'Javascript Regex pattern for Pilcrow (¶) or Partial Differential (∂) character';
// Match either ¶ (\u00B6) or ∂ (\u2202)
const matches = value.match(/[\u00B6\u2202]/gmi);
console.log(matches); // Output: ["¶", "∂"]

Example: Replace the Symbols

If you need to replace these characters with something else, use replace() with the same regex:

const replacedValue = value.replace(/[\u00B6\u2202]/gmi, '[SPECIAL_SYMBOL]');
console.log(replacedValue);
// Output: "Javascript Regex pattern for Pilcrow ([SPECIAL_SYMBOL]) or Partial Differential ([SPECIAL_SYMBOL]) character"

Solution 2: Match the Characters Directly #

If your text editor/terminal supports displaying these symbols correctly, you can also write them directly in the regex:

const matches = value.match(/[¶∂]/gmi);

This works too, but using Unicode escapes is safer if you're dealing with inconsistent encoding display (like the � you're seeing).

Verify the Actual Character Code (Just in Case) #

If you're unsure what Unicode code the problematic � represents, you can check it using charCodeAt():

// Grab the character from your string (replace index as needed)
const mysteryChar = value.charAt(35); // Example index for ¶ in your string
console.log(mysteryChar.charCodeAt(0).toString(16)); // Outputs "b6" for ¶, "2202" for ∂

This confirms you're targeting the right Unicode values.

内容的提问来源于stack exchange，提问作者Sean Delaney