使用discord.py的Discord机器人执行斜杠命令时出现Unknown Integration错误

环境：

• Python 3.11
• discord.py 框架
• PostgreSQL 数据库

需求：通过斜杠命令获取频道信息并存储到数据库中。已设置斜杠为命令前缀，Discord中命令可自动补全，但执行命令时，Discord聊天框显示Unknown Integration错误，VSCode终端无任何报错信息，同时数据库中也没有存入对应数据。

以下是获取频道信息并写入数据库的代码：

async def set_command_channel(interaction, command: str):
    connection = DB_Connection()
    conn = connection.db_connect()
    if conn is None:
        message = await interaction.response.send_message("❌ Failed to connect to the database.")
        return False, message

    try:
        cursor = conn.cursor()

        # Fetch the internal server ID
        fetch_server_sql = "SELECT id FROM server WHERE guild_id = %s;"
        cursor.execute(fetch_server_sql, (interaction.guild.id,))
        server_result = cursor.fetchone()

        if server_result is None:
            message = await interaction.response.send_message("❌ This server is not registered in the database.")
            return False, message

        # Explanation of `server_id = server_result[0]`
        # `cursor.fetchone()` returns a tuple, like (12,) — the first item is the internal 'id'
        server_id = server_result[0]

        insert_sql = '''
            INSERT INTO channel (channel_id, name, command, activator, join_date, server_id)
            VALUES (%s, %s, %s, %s, NOW(), %s)
            ON CONFLICT (channel_id)
            DO UPDATE SET
                name = EXCLUDED.name,
                command = EXCLUDED.command,
                activator = EXCLUDED.activator,
                join_date = EXCLUDED.join_date,
                remove_date = NULL,
                server_id = EXCLUDED.server_id;
        '''

        cursor.execute(
            insert_sql,
            (
                interaction.channel.id,
                interaction.channel.name,
                command,
                interaction.user.id,
                server_id
            )
        )

        conn.commit()
        message = await interaction.response.send_message(f"✅ Channel registered for `{command}` command!")
        return True, message

    except Exception as e:
        await interaction.response.send_message(f"❌ Database error: {e}")

    finally:
        cursor.close()
        conn.close()


# AI news channel setup.
@clients.tree.command(name="news", description="Get the latest AI news!")
async def set_news_channel(interaction):
    if interaction.response.is_done():
        # Already responded somehow (possible duplicate trigger)
        return

    try:
        await interaction.response.defer(thinking=True) 

        success, message = await set_command_channel(interaction, 'news')

        # Safe follow-up only
        if success:
            await interaction.followup.send("📡 Got it! You'll receive AI updates in this channel.")
        else:
            await interaction.followup.send(f"❌ {message}")

    except Exception as e:
        # Just in case there's an unexpected failure
        if not interaction.response.is_done():
            await interaction.response.send_message(f"⚠️ Error: {e}", ephemeral=True)
        else:
            await interaction.followup.send(f"⚠️ Error: {e}", ephemeral=True)

set_command_channel()协程用于其他需要配置频道并存储信息的方法，目前无法定位问题根源，希望得到帮助。

内容的提问来源于stack exchange，提问作者lony235