已知图像分辨率与中心点坐标，求解图像四角坐标

Absolutely! You can compute the four corner coordinates using the data you have—let's walk through this clearly, with key assumptions called out upfront.

Key Assumptions (Critical for Accuracy) #

First, we need to lock in a few ground rules since your question doesn't specify them (these are standard defaults unless you're working with a non-conventional coordinate system):

• Each pixel corresponds to 1x1 unit in the real world (you stated this, so we'll stick with it).
• The image's geometric center exactly matches the given center coordinate (-403059.626, -12869811.372).
• The real-world coordinate system uses:
  • Positive x = right (matches standard image pixel x-axis direction)
  • Positive y = up (note: some systems use positive y = down—we'll cover that adjustment later)

Step 1: Calculate Half-Dimensions of the Image #

Your image resolution is 4168×3632 pixels. Since we're working from the center, we need half the width and half the height:

• Half-width: 4168 / 2 = 2084 units
• Half-height: 3632 / 2 = 1816 units

Step 2: Compute Each Corner Coordinate #

Let’s denote the center coordinates as (Cx, Cy) = (-403059.626, -12869811.372). Using the half-dimensions, we calculate each corner:

• Top-left corner: (Cx - 2084, Cy + 1816) → (-403059.626 - 2084, -12869811.372 + 1816) = (-405143.626, -12867995.372)
• Top-right corner: (Cx + 2084, Cy + 1816) → (-403059.626 + 2084, -12869811.372 + 1816) = (-400975.626, -12867995.372)
• Bottom-right corner: (Cx + 2084, Cy - 1816) → (-403059.626 + 2084, -12869811.372 - 1816) = (-400975.626, -12871627.372)
• Bottom-left corner: (Cx - 2084, Cy - 1816) → (-403059.626 - 2084, -12869811.372 - 1816) = (-405143.626, -12871627.372)

Adjustment for Reverse Y-Axis #

If your real-world coordinate system uses positive y = down (common in some image processing workflows), flip the sign on the y-component calculations:

• Top-left: (Cx - 2084, Cy - 1816)
• Top-right: (Cx + 2084, Cy - 1816)
• Bottom-right: (Cx + 2084, Cy + 1816)
• Bottom-left: (Cx - 2084, Cy + 1816)

Final Note #

As long as you confirm the coordinate axis directions and that the given center is indeed the image's geometric center (not a pixel center offset), these calculations will be accurate.

内容的提问来源于stack exchange，提问作者tourist