如何关闭qx.ui.treevirtual.TreeVirtual树的所有分支？报错nodeSetOpened非函数

Got it, let's fix this issue right away! The error 'nodeSetOpened is not a function' happens because you're calling this method on the TreeVirtual instance itself—but nodeSetOpened isn't a method of qx.ui.treevirtual.TreeVirtual. Instead, all node state management (like opened/closed status) is handled by the tree's data model (qx.ui.treevirtual.SimpleTreeDataModel), which has the methods you need.

Here's the corrected code #

We'll adjust the code to call the method on the data model, plus some small optimizations to avoid repeated calls to getDataModel():

this._tree.addListener("dblclick", function(e) {
  // Cache the data model to avoid repeated lookups
  const treeModel = this._tree.getDataModel();
  const rowCount = treeModel.getRowCount();
  
  for (let i = 0; i < rowCount; i++) {
    const child = treeModel.getNode(i);
    // Simplify the condition (no need to compare `== true`)
    if (child.level === 1 && child.bOpened) {
      // Option 1: Use row index to close the node
      treeModel.setOpened(i, false);
      
      // OR Option 2: Use the node object directly (if you prefer)
      // treeModel.nodeSetOpened(child, false);
    }
  }
}, this);

Key Explanations #

• Why this works: TreeVirtual is just the UI component—all node data and state (like bOpened) lives in its data model. The data model provides two valid methods to close nodes:
  • setOpened(rowIndex, isOpened): Takes the row index of the node and a boolean to set its opened state.
  • nodeSetOpened(node, isOpened): Takes the node object itself and a boolean to set its state.
• Optimization: Caching treeModel and rowCount reduces redundant method calls, making your code a bit more efficient.
• Cleaner condition: child.bOpened is already a boolean, so comparing it to true is unnecessary.

内容的提问来源于stack exchange，提问作者Raymond