如何基于输入数字n生成特定形状的数字方阵？

Hey Jesse, I get stuck on these "simple-looking" pattern problems all the time too—they're tricky because the logic isn't obvious at first glance! Here are a couple of direction hints to help you untangle this without giving away the full solution:

• Think in layers/rings: Imagine the grid as a series of concentric rings. For n=3, the outer ring holds numbers 1-8, and the inner single cell is 9. Try figuring out how to fill each ring clockwise, starting from the top-left corner. You can define the boundaries of each ring (like top row, right column, bottom row, left column) and increment your number as you traverse each edge of the ring, then move inward to the next ring once the outer one is done.
• Map coordinates to values directly: Instead of filling row by row, try calculating the exact number that should go in position (i,j) (where i is the row index, j is the column index). Look for patterns based on how far the position is from the edges of the grid—for example, the distance from the top, right, bottom, or left might help you determine which "side" of a ring it's on, and from there compute the number.

Here's your current code snippet for reference:

public class DrawSquareWithNumbers { 
    public static void main(String[] args) { 
        Scanner scanner = new Scanner(System.in); 
        System.out.println("Enter your number: "); 
        int number = scanner.nextInt(); 
        for (int i = 0; i <= number; i++) { 
            if (i<number) System.out.print(i); 
            if (i>=number) { 
                System.out.println("\n"+i); 
            } 
        } 
    } 
}

And just to recap the expected outputs you shared:
For input 2:

12
43

For input 3:

123
894
765

内容的提问来源于stack exchange，提问作者Jesse James