为何我的骰子游戏条件判断代码失效，朋友的却正常运行？

Hey there! Let's walk through why your dice game code isn't behaving as expected, even though it looks similar to your friend's working version. There are a few key logic and syntax issues throwing things off:

1. 核心条件判断逻辑错误（非1的判断） #

Your code uses:

if (dice !== 1 || diceTwo !== 1) {

This condition means "if either die is NOT 1" — which will still trigger the scoring branch even if one die IS 1 (e.g., dice=1, diceTwo=2 would pass this check). But according to your rules, we should only enter the scoring branch if neither die is 1. You need to use && instead of || here:

if (dice !== 1 && diceTwo !== 1) {

2. 连续6的判断不完整 #

Your code checks for consecutive sixes with:

if (doubleSix === 6 && dice === 6) {

This only looks at the first die (dice) being 6, but your rule applies if either die is 6 on the second roll. You need to include diceTwo here, matching your friend's logic:

if (doubleSix === 6 && (dice === 6 || diceTwo === 6)) {

3. 分数清空范围错误 #

You're resetting the entire score variable to 0 with:

score = 0;

But this should only reset the active player's score, not all players' scores. Use the same approach as your friend:

score[activePlayer] = 0;

4. 语法错误（无效的else if） #

Your code has a broken else if with no condition:

} else if {

This is invalid syntax — since you've already checked the consecutive sixes condition, the remaining case is just normal scoring, so you should use a plain else instead.

修正后的完整代码 #

Here's your code with all the fixes applied, which should match your friend's working logic:

if (dice !== 1 && diceTwo !== 1) { 
  // Add score
  if (doubleSix === 6 && (dice === 6 || diceTwo === 6)) {
    roundScore = 0;
    score[activePlayer] = 0;
    nextPlayer();
  } else {
    roundScore += (dice + diceTwo);
    document.querySelector('#current-' + activePlayer).textContent = roundScore;
    doubleSix = dice;
  }
} else { 
  // Next Player
  nextPlayer();
}

Let's confirm the logic now matches your rules:

• If either die rolls a 1: switch players immediately
• If neither die is 1, but we had a 6 on the last roll and now roll a 6 on either die: reset current and player scores, then switch players
• Otherwise: add the dice total to the round score, update the display, and save the current die value for checking consecutive sixes next round

内容的提问来源于stack exchange，提问作者LiamOakley