如何合并元组列表中各元组元素并转换为指定嵌套列表格式？

Sure thing! Here are two straightforward ways to achieve your desired output:

Convert Existing List A #

If you already have the list of tuples A and just need to transform it, you can use a list comprehension to process each tuple:

A = [(1, 2, 3), (3, 4, 5), (3, 5, 7)]
result = [[int(''.join(map(str, t)))] for t in A]
print(result)  # Output: [[123], [345], [357]]

How this works: #

• map(str, t) converts each integer in the tuple t to a string (e.g., (1,2,3) becomes ['1','2','3']).
• ''.join(...) concatenates those strings into a single string (e.g., '123').
• int(...) converts the concatenated string back to an integer (e.g., 123).
• Wrapping the result in [] turns it into a single-element list, and the outer list comprehension applies this to every tuple in A.

Modify Your Converter Function #

To get the desired output directly from your permutation-generating function, you can modify the return statement to process each permutation tuple before returning it. Don't forget to import itertools if you haven't already:

import itertools

def converter(N):
    y = list(str(N))
    t = [int(x) for x in y]
    permutations = list(itertools.permutations(t))
    # Process each permutation into the desired format
    return [[int(''.join(map(str, perm)))] for perm in permutations]

r = converter(345)
print(r)
# Output: [[345], [354], [435], [453], [534], [543]]

This way, the function returns the permutations already formatted as single-element lists containing the concatenated integer, instead of tuples of individual digits.

内容的提问来源于stack exchange，提问作者camarman