Python 3.6代码运行报错NameError: name 'room_path' is not defined求助

API 探路者

2026-5-29

Fixing NameError: name 'room_path' is not defined in Your Python 3.6 Code

Hey there! Let's get that NameError sorted out, plus fix a couple other sneaky issues in your code.

First: The Root Cause of the `NameError`

Python relies heavily on indentation to define code blocks, and your function room() doesn't have proper indentation for its body. On top of that, you never actually call the function to run the code inside it!

In your original code, the room_path list is defined inside the function, but since the function body isn't indented correctly and you never call room(), that variable never gets created in the scope where your if statement is running. Hence the NameError.

Second: Fixing the Code (Step by Step)

Here's the corrected version with explanations:

def room():
    # Properly indent all code inside the function (4 spaces is Python's standard)
    room_path = ["1", "2"]
    user_choice = ""
    print("If you decide to ditch Todd and go to the campfire alone, enter 1")
    print("If you decide to drag Todd with you to the campfire, enter 2")
    user_choice = input("your option number: ")
    
    # Python uses 0-based indexing! Your original code used [1] and [2], which is wrong
    if user_choice == room_path[0]:  # Matches "1" (first option)
        print("yes")
    elif user_choice == room_path[1]:  # Matches "2" (second option)
        print("no")

# Don't forget to call the function to execute its code—defining it doesn't run it!
room()

Key Fixes Made:

Indentation: All lines inside room() are indented so they're recognized as part of the function's body.
0-Based Indexing: Python lists start counting from 0, so room_path[0] targets "1" and room_path[1] targets "2" (your original room_path[2] would have caused an IndexError anyway).
Function Call: Added room() at the end to actually run the code inside your function.