Python实现8x8 LED矩阵字符循环移动动画方案咨询

我最近在写Python脚本控制8x8 LED矩阵，碰到了个实现字符动画效果的问题，想请教下大家！我希望能让矩阵上的字符实现从右到左、从左到右、从上到下、从下到上的移动动画。

已完成的基础工作 #

我先为字母E创建了对应的8x8矩阵数据：

matrix = [
    "1","1","1","1","1","1","1","1",
    "1","1","1","1","1","1","1","1",
    "1","1","0","0","0","0","0","0",
    "1","1","1","1","1","0","0","0",
    "1","1","1","1","1","0","0","0",
    "1","1","0","0","0","0","0","0",
    "1","1","1","1","1","1","1","1",
    "1","1","1","1","1","1","1","1"
]

对应的字母E显示效果：

具体动画需求 #

我想实现字母E的移动动画，比如向左移动时：

• 先让第八列变为空白
• 间隔1秒后第七列也变为空白，以此类推
• 等整个矩阵完全空白后，字母E从右侧重新出现

想请教下，怎么利用数组、矩阵这类数据结构来实现这个效果？

附测试代码 #

我写了一段测试代码，用来尝试左移逻辑，大家可以参考：

matrix = [
    [0, 0, 0, 1, 0],
    [0, 0, 0, 1, 0],
    [0, 0, 0, 1, 0],
    [0, 0, 0, 1, 0],
    [0, 0, 0, 1, 0]
]
print(matrix)

def shift(my2dArray):
    for _ in range(5): # 尝试左移5次
        for row in my2dArray:
            row.pop(0) # 删除每行的第一个元素
            row.append("0") # 在每行末尾添加"0"作为空白
        # 这里应该添加更新显示和延时的代码

shift(matrix)
print(matrix)

内容的提问来源于stack exchange，提问作者Naografix