TypeScript中如何实现对象赋值并替换对象名称？

Hey there, let's break down how to nail this exactly how you want it.

First, your core goal: make a fresh newMember object that copies all properties from data.response.details (replacing the original details object). Let's walk through what works, and adjust if needed.

Your Current Code (It's Already Correct!) #

Your existing approach is actually spot-on for copying the details properties into newMember. Let's look at it again:

public after(args: IResult, data: any) {
  const res: IResult = data.response.details;
  const newMember = Object.assign({}, res);
  return Promise.resolve(this.getInformation(args, newMember));
}

Here's the breakdown:

• Object.assign({}, res) creates a blank new object ({}) as the target, then copies every enumerable property from res (your data.response.details) into it.
• The result? newMember will be an exact duplicate of your original details object, which matches the structure you want:

{
  "patientProfile": {
    "firstName": "Rob",
    "lastName": "ALLen",
    "memberStatus": "Active"
  }
}

If You Need a Top-Level newMember Key #

If you actually want to wrap this copied object into a parent object with a top-level "newMember" key (like your sample expected JSON shows), just tweak the code slightly:

public after(args: IResult, data: any) {
  const res: IResult = data.response.details;
  // Wrap the copied object into a parent with the "newMember" key
  const wrappedResult = { newMember: Object.assign({}, res) };
  return Promise.resolve(this.getInformation(args, wrappedResult));
}

This will give you the exact JSON structure you listed:

{
  "newMember": {
    "patientProfile": {
      "firstName": "Rob",
      "lastName": "ALLen",
      "memberStatus": "Active"
    }
  }
}

Quick Heads-Up: Shallow vs. Deep Copy #

One thing to note: Object.assign does a shallow copy. That means if patientProfile had nested objects inside it, those nested items would still reference the original ones from data.response.details. If you need a full deep copy (where even nested objects are duplicated), you could use JSON.parse(JSON.stringify(res)) for simple data structures, or a dedicated deep copy utility for more complex data (like functions or special types). But for your current example, a shallow copy is totally enough.

内容的提问来源于stack exchange，提问作者hussain