如何利用预定义Grok过滤器拼接sendid与邮箱地址并提取?
sendid:<email> String from Sendmail Logs I get that you want to capture the complete sendid:name@test.co.uk string from your sendmail logs—instead of just the email address part—without creating extra fields or custom Grok patterns beyond standard inline captures. Here's how to make it work:
Correct Grok Pattern
Use a single capture group that wraps both the sendid: prefix and the email address (stopping at the next comma in your log format):
(?<DATA>sendid:[^,]+)
How It Works
(?<DATA>...): This defines a capture group that stores the matched content in a field namedDATA, aligning with your desired output structure.sendid:: Matches the literal prefix exactly, ensuring we only target entries with this marker.[^,]+: Matches all characters until the next comma (which marks the end of thesendidentry in your log line, right beforedelay=...).
Testing in Grok Debugger
When you plug your log line into the debugger with this pattern, it will capture the full sendid:name@test.co.uk string into the DATA field. You can then format the output into your desired JSON structure (like { "DATA": [ [ "sendid:name@test.co.uk" ] ] }) via your pipeline configuration (e.g., Logstash's json filter or output settings).
Why Your Previous Attempts Didn't Work
sendid:%{DATA},: This only captures the email address becausesendid:is treated as a literal match (not part of the captured data), and%{DATA}only grabs the content after the prefix until the comma.sendid:%{"sendid:"} %{DATA},: This uses invalid Grok syntax—Grok doesn't support embedding strings like%{"sendid:"}within patterns.
内容的提问来源于stack exchange,提问作者MaverickD

