Python中random.shuffle返回None及生成3D点列表的问题

Hey there, let's break down your two Python issues one by one!

This is super common for folks new to Python's random module! random.shuffle() is an in-place operation—it modifies the list you pass directly, instead of creating and returning a brand new shuffled list. That's why it always returns None.

In your code, after calling random.shuffle(c), the original list c is already shuffled. You don't need to assign the result to z—just print c directly to see the shuffled version.

Here's a fixed version of your code:

import random
a = list(range(1,99))
b = list(range(1,99))
c = list(range(1,99))

print("Original c:", c)
random.shuffle(a)
random.shuffle(b)
random.shuffle(c)
# Now a, b, c are all shuffled in-place
print("Shuffled c:", c)

If you don't want to modify the original list and need a new shuffled list instead, use random.sample()—it returns a new list while leaving the original untouched:

import random
c = list(range(1,99))
z = random.sample(c, k=len(c))  # k specifies how many elements to take (all here)
print("Original c:", c)
print("New shuffled list z:", z)

Your code fails because len(x,y,z) is invalid syntax—len() only accepts one iterable as an argument, not multiple. Also, you need to make sure x, y, z are three lists of the same length (each storing the x/y/z coordinates of your points).

Here are two solid ways to implement this:

Option 1: Use zip() (recommended) #

zip() packs corresponding elements from multiple lists into tuples, making it easy to iterate through each 3D point:

# First, prepare your coordinate lists (same length)
x_coords = [1, 2, 3, 4]
y_coords = [5, 6, 7, 8]
z_coords = [9, 10, 11, 12]

# Generate all 3D points and store them in a list
points = []
for x, y, z in zip(x_coords, y_coords, z_coords):
    points.append((x, y, z))

# Or use a list comprehension for a shorter version
points = [(x, y, z) for x, y, z in zip(x_coords, y_coords, z_coords)]

print(points)
# Output: [(1, 5, 9), (2, 6, 10), (3, 7, 11), (4, 8, 12)]

Option 2: Loop with indexes #

If you prefer using indexes, just grab the length of one list (make sure all three are the same length first):

x_coords = [1, 2, 3, 4]
y_coords = [5, 6, 7, 8]
z_coords = [9, 10, 11, 12]

points = []
# Use the length of x_coords as the loop count
for i in range(len(x_coords)):
    point = (x_coords[i], y_coords[i], z_coords[i])
    points.append(point)

print(points)

Quick note: Avoid creating dynamic variables like q1, q2, q3—storing all points in a list is way easier to work with later (you can loop through them, index them, etc.).

内容的提问来源于stack exchange，提问作者tgmjack