Android中如何将JSONObject内的对象批量转换为JSONArray

Got it, dealing with 100+ manual getJSONObject() calls is definitely a pain—let's fix that with automatic iteration. Here's how you can loop through all keys in your charts object and add each chart to a JSONArray without manual work:

First, forget the index-based for loop you started with—JSONObject doesn't work that way. Instead, we'll use the keyset of the JSONObject to iterate through every unique key (like "system_voltage", "temperature1", etc.).

Step-by-Step Code Implementation #

// Your existing line to get the charts JSONObject
JSONObject chartss = objData.getJSONObject("charts");

// Initialize the JSONArray that will hold all chart objects
JSONArray chartArray = new JSONArray();

// Get an iterator for all keys in the charts JSONObject
Iterator<String> chartKeys = chartss.keys();

// Loop through each key
while (chartKeys.hasNext()) {
    String currentKey = chartKeys.next();
    // Fetch the chart object for the current key
    JSONObject singleChart = chartss.getJSONObject(currentKey);
    // Add this chart object to the JSONArray
    chartArray.put(singleChart);
}

// Now chartArray contains all your chart objects, ready to use!

How This Works #

• chartss.keys() returns an iterator over all top-level keys in your charts JSONObject—perfect for handling any number of entries, whether it's 3 or 300.
• For each key, we fetch the corresponding chart object using getJSONObject(currentKey) and add it directly to the JSONArray.
• Since all keys in a JSONObject are unique (as you mentioned), you don't have to worry about duplicates or missing entries.

Optional: Keep Track of Keys (If Needed) #

If you need to retain the original key (like "system_voltage") alongside the chart data, you can modify each chart object to include the key as a new field before adding it to the array:

while (chartKeys.hasNext()) {
    String currentKey = chartKeys.next();
    JSONObject singleChart = chartss.getJSONObject(currentKey);
    // Add the key as a new property (e.g., "chart_id")
    singleChart.put("chart_id", currentKey);
    chartArray.put(singleChart);
}

内容的提问来源于stack exchange，提问作者asus