求助：根据给定环境图编写触发对应计算的Scheme代码

Let's work through the issues in your current code and adjust it to trigger the computation process shown in your diagram.

First, here are the key problems with your snippet:

• The anonymous lambda ((lambda(y) (+ y 5))) is missing an argument—this will throw an error because it expects a value for y but none is provided.
• Your goo function is an infinite recursive loop: (lambda (args) (goo args)) calls itself indefinitely with no base case, so it will never terminate.
• The let expression in foo is incomplete, so we need to fill it in to match typical environment diagram behavior.

Corrected Code Example #

Assuming your diagram shows foo taking a function argument (shadowing the global goo), using let to define a local variable, and invoking the passed function, here's a working version that aligns with that flow:

; Define foo to take a function argument (named goo, shadowing the global one)
(define foo
  (lambda (goo)
    (let ((local-value 10))  ; Create a local binding inside foo
      (goo local-value))))   ; Call the passed function with the local value

; Define global goo to take a function and return a new function
(define goo
  (lambda (func)
    (lambda (num)
      ((lambda (y) (+ y 5)) (func num)))))  ; Apply the inner lambda to func's result

; Trigger the computation: pass the result of goo to foo
(foo (goo (lambda (x) (* x 2))))

Step-by-Step Computation (Matching the Environment Diagram) #

1. Global Environment: We define foo and goo here.
2. Calling (goo (lambda (x) (* x 2))):
   • A new environment is created where func is bound to the lambda (lambda (x) (* x 2)).
   • goo returns a new lambda: (lambda (num) ((lambda (y) (+ y 5)) ((* num 2)))).
3. Calling (foo <returned-lambda>):
   • A new environment is created for foo's parameters, where the local goo is bound to the lambda returned by goo.
   • Inside foo, let creates a binding for local-value to 10.
   • We call (goo local-value): this invokes the returned lambda with 10 as num.
4. Inside the returned lambda:
   • A new environment binds num to 10. We first compute (* 10 2) = 20.
   • We then invoke the inner lambda (lambda(y) (+ y 5)) with 20 as y, resulting in 20 + 5 = 25.

If your diagram has a different structure (e.g., goo directly applying the lambda instead of returning a function), let me know and we can adjust further!

内容的提问来源于stack exchange，提问作者谞讬专讬讬讘 砖诪讜讗诇