如何将解构导入的指定模块成员整合为单个对象？

First off, let's break down why your attempted syntax throws an error:

JavaScript's ES module import syntax doesn't support using as to bundle destructured named exports directly into a new object. The as keyword only works for two cases:

• Renaming a single export (e.g., import { A as filterA } from '@/helpers/filters')
• Importing the entire module as a namespace object (e.g., import * as allFilters from '@/helpers/filters')

So your line import { A, B, C } as filters from '@/helpers/filters' violates the syntax rules, hence the "Expression statement is not assignment or call" error.

Solution 1: Your Original (and Most Readable) Approach #

Your initial two-line code is already clean and easy to understand—this is the most recommended approach for balance of brevity and readability:

import { A, B, C } from '@/helpers/filters';
const filters = { A, B, C };

Solution 2: Namespace Import + Object Destructuring #

If you want to condense things a bit more, you can import the full module namespace first, then extract and bundle the functions you need:

import * as allFilters from '@/helpers/filters';
const filters = { A: allFilters.A, B: allFilters.B, C: allFilters.C };

Or use object destructuring to make it even cleaner:

import * as allFilters from '@/helpers/filters';
const { A, B, C } = allFilters;
const filters = { A, B, C };

Solution 3: One-Liner with Dynamic Import (Async Context Only) #

For a true one-liner, you can use dynamic import() combined with an IIFE (Immediately Invoked Function Expression)—just note this requires an async context:

const filters = (({ A, B, C }) => ({ A, B, C }))(await import('@/helpers/filters'));

Or handle the promise explicitly if you can't use await:

import('@/helpers/filters').then(({ A, B, C }) => {
  const filters = { A, B, C };
  // Your logic here
});

At the end of the day, your original approach is the best choice for most cases—it's straightforward and doesn't sacrifice readability for the sake of brevity.

内容的提问来源于stack exchange，提问作者van_folmert