Swift中如何对字典按键排序并同步排序对应数组值

To get your dictionary sorted by keys with each corresponding array value also sorted, here's a straightforward approach tailored to Swift:

Step-by-Step Breakdown #

1. Sort each value array: For every entry in your original dictionary, we’ll sort the integer array in ascending order (easy to adjust if you need descending).
2. Sort entries by key: Take those processed key-value pairs and sort them alphabetically by their string keys.
3. Build the ordered dictionary: Convert the sorted entries back into a dictionary. Since Swift 5.1, the standard Dictionary preserves insertion order when using unique keys, so your sorted order will stay intact when you iterate over it.

Full Code Implementation #

var dicNumArray: Dictionary<String, [Int]> = ["q":[4,3,2,1,5],"a":[2,3,4,5,5],"s":[123,123,132,43,4],"t":[0,88,66,542,321]]

// Process and sort the dictionary in one chain
let sortedDictionary = Dictionary(uniqueKeysWithValues:
    dicNumArray.map { (key, values) in
        (key, values.sorted()) // Sort each array's integers
    }
    .sorted { $0.0 < $1.0 } // Sort entries by key in ascending order
)

// Verify the result
print(sortedDictionary)

Expected Result #

When you run this code, you’ll get the following output:

["a": [2, 3, 4, 5, 5], "q": [1, 2, 3, 4, 5], "s": [4, 43, 123, 123, 132], "t": [0, 66, 88, 321, 542]]

Quick Customizations #

• Reverse key order: To sort keys from Z to A, change the sorted closure to $0.0 > $1.0.
• Reverse array order: To sort each integer array from largest to smallest, replace values.sorted() with values.sorted(by: >).

内容的提问来源于stack exchange，提问作者Nassif