如何在包含range的Python列表中查找指定值？

Hey there! Let's break down why your current code isn't working and get it sorted out.

The Problem with Your Original Code #

Your code tries to check if (5,12) is in the list, but the list contains (5, range(10,15))—these are not the same thing. Python's in operator does a strict equality check: it compares the entire tuple, and since one has an integer as the second element and the other has a range object, it can't find a match. Also, a couple of syntax issues: you shouldn't use list as a variable name (it overwrites Python's built-in list type), and Print should be lowercase print.

The Correct Approach #

We need to check two conditions for each tuple in the list:

• The first element of the tuple matches your target's first value (5 in this case)
• Your target's second value (12) is contained within the range object in the tuple's second position

Solution Code Examples #

First, properly set up your list (avoid using list as a variable name):

# Initialize your list with a descriptive name
my_list = []
# Add the tuple containing a range
my_list.append((5, range(10, 15)))

Option 1: Explicit Loop

This is straightforward and easy to follow:

target = (5, 12)
is_found = False

for item in my_list:
    # Check both conditions: matching first element, and value in range
    if item[0] == target[0] and target[1] in item[1]:
        is_found = True
        break

if is_found:
    print("yes")
else:
    print("no")

Option 2: Concise any() Function

For a more compact solution, use Python's any() function, which returns True if any element in the iterable meets the condition:

target = (5, 12)
if any(item[0] == target[0] and target[1] in item[1] for item in my_list):
    print("yes")
else:
    print("no")

Both of these will correctly detect that 12 is within range(10,15) and that the first element matches 5, so they'll print "yes" as expected.

内容的提问来源于stack exchange，提问作者Alberto Pani