Java正则表达式处理逗号分隔字符串：提取每个块的第三个[]值

Since you need a one-liner for JasperReport's text field expression (which runs on Java under the hood), you can use a targeted regex with replaceAll() to directly transform your input string into the desired output.

The One-Liner Code #

$F{yourInputField}.replaceAll("\\[[^\\]]+\\]\\.\\[[^\\]]+\\]\\.\\[([^\\]]+)\\]", "$1")

How It Works #

Let’s break down the regex to make it clear:

• \\[[^\\]]+\\]: Matches a single bracket pair like [xxx] — the [^\\]]+ ensures we capture everything inside the brackets except the closing ].
• \\.: Escapes the literal dot between bracket groups (dots are special characters in regex, so we need to escape them).
• We repeat the first two parts (\\[[^\\]]+\\]\\.) twice to skip the first two bracket pairs in each comma-separated block.
• \\[([^\\]]+)\\]: Matches the third bracket pair and captures its content into group $1.

When you run replaceAll(), every full block like [A].[B].[C] gets replaced with just C, while the comma and space separators between blocks stay intact. This gives you exactly the output you want: Mk Alprazolam, Mk Amantadina.

Example Usage #

If your input string is stored in a Jasper field named rawString, your text field expression would be:

$F{rawString}.replaceAll("\\[[^\\]]+\\]\\.\\[[^\\]]+\\]\\.\\[([^\\]]+)\\]", "$1")

内容的提问来源于stack exchange，提问作者Jose Antonio Hernandez Gil