如何将用户输入的逗号分隔10个数字存入C语言数组？

Hey there! Let's break down what's going wrong with your current code and fix it so you can properly read 10 comma-separated numbers into your array.

First, let's spot the issues in your original code: #

• Array Out-of-Bounds Error: You're using &A[10] as the argument for scanf, but your array A only has indices from 0 to 9. Accessing A[10] is undefined behavior—it's memory that doesn't belong to your array.
• Only Reads One Number: Your scanf call only reads a single integer, and doesn't handle the commas separating the numbers, nor does it loop to read all 10 values.

Solution 1: Simple Loop with scanf (Strict Comma Separation) #

If your users will input numbers strictly in the format num1,num2,num3,...num10 (with or without spaces around commas), this straightforward loop will work perfectly:

#include <stdio.h>
int main () {
    int A[10]; // 存储用户输入的数组
    printf("Enter your numbers: ");

    // 读取前9个数字，每个后面跟着逗号
    for (int i = 0; i < 9; ++i) {
        // %d, 表示读取整数后跳过逗号（自动忽略空格）
        scanf("%d,", &A[i]);
    }
    // 读取第10个数字，后面没有逗号
    scanf("%d", &A[9]);

    // 可选：验证输入是否正确存储
    printf("\nYour array contains:\n");
    for (int i = 0; i < 10; ++i) {
        printf("%d ", A[i]);
    }
    printf("\n");

    return 0;
}

How this works:

• The format specifier %d, tells scanf to read an integer, then skip over the following comma (it also automatically ignores any whitespace around the comma, so inputs like 123 , 456 still work).
• We handle the 10th number separately since it won't have a trailing comma.

Solution 2: Robust Line Reading with String Parsing #

If you want to handle more flexible input (like extra spaces, accidental newlines, or partial input), reading the entire line first and then parsing it is a better approach. Here's how to do that with fgets and strtok:

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

int main () {
    int A[10];
    char input_buffer[200]; // 足够容纳输入的缓冲区
    printf("Enter your numbers: ");

    // 读取整行输入（包括所有逗号和空格）
    if (fgets(input_buffer, sizeof(input_buffer), stdin) == NULL) {
        printf("Error reading input!\n");
        return 1;
    }

    // 使用strtok分割输入，逗号、空格、换行符都作为分隔符
    char* token = strtok(input_buffer, ", \n");
    int count = 0;

    while (token != NULL && count < 10) {
        // 将分割后的字符串转为整数
        A[count] = atoi(token);
        // 获取下一个分割后的片段
        token = strtok(NULL, ", \n");
        count++;
    }

    // 检查是否读取了足够的数字
    if (count < 10) {
        printf("Warning: Only %d numbers were entered (expected 10).\n", count);
    }

    // 验证输出
    printf("\nYour array contains:\n");
    for (int i = 0; i < count; ++i) {
        printf("%d ", A[i]);
    }
    printf("\n");

    return 0;
}

Why this is better:

• fgets captures the entire input line, avoiding issues with leftover newline characters from scanf.
• strtok splits the input on commas, spaces, and newlines, so messy inputs like 123 ,456 , 789\n are handled correctly.
• We add a check to warn if fewer than 10 numbers were entered, making the code more user-friendly.

内容的提问来源于stack exchange，提问作者user9741196