统计名称以)x结尾的文件夹数量的批处理脚本问题

Got it, let's fix that batch script for you. The issue with your attempt is twofold: first, you're looking for directories named exactly )x instead of those ending with that string, and second, the closing parenthesis ) is a special character in batch that needs to be escaped so it's treated as part of the filename pattern.

Here's the corrected script:

@echo off
set "count=0"
for /d %%a in (*^)x) do set /a count+=1
echo Number of directories ending with ")x": %count%

Let me break down what's happening here:

• @echo off keeps the command prompt from showing each line as it runs, making the output cleaner.
• set "count=0" initializes our counter to zero—this ensures we start from a known value instead of whatever might have been in the variable before.
• for /d %%a in (*^)x): The /d flag tells the loop to target directories instead of files. The pattern *^)x is key here:
  • * matches any sequence of characters at the start of the directory name.
  • ^) escapes the closing parenthesis so batch doesn't interpret it as the end of the loop's input set.
  • x finishes the pattern, so we only match names that end with )x.
• set /a count+=1 increments the counter by 1 for each matching directory.
• Finally, we echo out the total count using %count%.

If you need to do more complex operations inside the loop (like accessing the updated count while the loop is running), you'll want to enable delayed expansion. Here's that version:

@echo off
setlocal enabledelayedexpansion
set "count=0"
for /d %%a in (*^)x) do (
    set /a count+=1
    echo Found matching directory: %%a, current count: !count!
)
echo Total matching directories: !count!
endlocal

The setlocal enabledelayedexpansion lets us use !count! to access the updated value of the counter inside the loop, which is necessary because batch normally expands variables before running the loop.

内容的提问来源于stack exchange，提问作者Henrik