Hey there, let's work through this PDO error you're hitting—it's a common gotcha with parameter binding, so we can track it down quickly. The HY093 error means your SQL statement has more named/positional parameters than you're actually passing to execute(), or there's a mismatch between the parameter names in your query and the ones you're binding.

Here are the key steps to debug:

1. Check Your SQL Statement & Parameter Count in doedit.php #

First, look at the prepared SQL query around line 47. Let's say it looks like this:

$sql = "UPDATE your_table SET column1 = :val1, column2 = :val2 WHERE id = :id";
$stmt = $pdo->prepare($sql);

Count the number of placeholder parameters (the :something parts). Then check how many parameters you're passing to execute(). If the counts don't match—like you only pass ['val1' => $val1, 'val2' => $val2] but forget 'id' => $id—you'll get this error immediately.

2. Verify Parameter Name Spelling & Case Sensitivity #

PDO's named placeholders are case-sensitive. If your query uses :userId but you try to bind :userid (lowercase d), PDO will treat them as two distinct parameters. Double-check that every placeholder name in your SQL exactly matches the keys in the array you pass to execute(), or the names you use with bindParam()/bindValue().

3. Confirm the ID Parameter is Being Passed From edit.php to doedit.php #

Since your edit flow relies on edit.php (with an id parameter) and doedit.php, make sure the id is actually making the trip:

• In edit.php, ensure you have a hidden input field that includes the record's id:

  <input type="hidden" name="id" value="<?php echo htmlspecialchars($record_id); ?>">
  

• In doedit.php, check that you're retrieving the id correctly (e.g., $id = $_POST['id']; or $_GET['id'], depending on your form's method). If the id isn't present, even if you include it in your parameter array, an undefined variable could throw off the binding.

Example of a Quick Fix #

If your original code was missing the id parameter in execute():

// Wrong - missing the :id placeholder match
$stmt->execute([
    'val1' => $_POST['val1'],
    'val2' => $_POST['val2']
]);

The corrected version would include all required parameters:

// Correct - all placeholders are matched with values
$stmt->execute([
    'val1' => $_POST['val1'],
    'val2' => $_POST['val2'],
    'id' => $_POST['id']
]);

Start with these checks—9 times out of 10, this error comes down to a simple mismatch between the query's placeholders and the parameters you're passing.

内容的提问来源于stack exchange，提问作者Teixeira José