Python中如何将字符串有序分割后存入列表对应索引位置

Let's break down what's happening with your code first:

• When you run a=['fi lou you'.split()], the split() method already returns a list ['fi', 'lou', 'you'], but you're wrapping that result inside another set of square brackets. So you end up with a list containing a list: [['fi', 'lou', 'you']]. That's why trying to access a[0] gives you the whole sublist instead of the first string element.

The Solution #

Simply remove the outer square brackets when assigning to a. Since split() directly outputs the list you need, you can assign it directly:

a = 'fi lou you'.split()

Let's Verify #

If you run this corrected code, you'll get the behavior you want:

• a[0] will be 'fi'
• a[1] will be 'lou'
• a[2] will be 'you'

To confirm, you can print the value of a itself: it will be exactly ['fi', 'lou', 'you'], no nested lists involved!

内容的提问来源于stack exchange，提问作者David