使用shutil.make_archive压缩文件异常：压缩包内含损坏文件

Oh I’ve run into this exact problem before! Let’s break down what’s happening and get it fixed.

Root Cause #

The core issue here is that your output zip file is being created inside the directory you’re trying to compress. When shutil.make_archive runs, it attempts to archive the entire C:\Users\test folder—including the partially written zip file that’s being generated there. This circular write/read operation leads to the corrupted zip_file entry in your final archive.

Solutions #

1. Save the Archive Outside the Target Directory #

The first argument to make_archive is the base path of your output file (without the extension). Instead of using a relative name like zip_file (which defaults to your current working directory), specify an absolute path that’s outside the folder you’re compressing.

Example:

import shutil
# Save the zip to your Users folder, not inside the test folder
shutil.make_archive(r'C:\Users\zip_file', 'zip', r'C:\Users\test')

Pro tip: Use raw strings (r'path') for Windows paths to avoid escape character headaches.

2. Archive Folder Contents (Not the Folder Itself) #

If you don’t want the test folder to be the top-level entry in your zip, use the base_dir parameter to target the folder’s contents directly. This also helps avoid accidental inclusion of the output zip if you’re careful with the save path.

Example:

import shutil
target_dir = r'C:\Users\test'
# Save the zip outside the target directory, and archive just its contents
shutil.make_archive(r'C:\Users\zipfile_name', 'zip', root_dir=target_dir, base_dir=target_dir)

When you open this zip, you’ll see all files/subfolders from test directly, rather than wrapped inside a test folder.

Your second code snippet likely worked because either:

• You saved the archive outside the target directory, or
• The base_dir parameter prevented the tool from archiving the parent folder (and thus the zip file being created).

内容的提问来源于stack exchange，提问作者Drake .C