如何通过循环拆分重组列表：每6个元素为一组存储航司信息

Got it, let's fix this grouping issue you're dealing with! Since each airline's full data (name + 4 fees + description) takes exactly 6 consecutive elements in your list, we can easily split the list into chunks of 6 using a simple loop or Pythonic list comprehension.

Step-by-Step Solution with Loop #

Here's a straightforward for-loop approach that’s easy to follow and tweak if you need adjustments later:

myList = ['Southwest', '0', '0', '0', '0', 'Yes!', 'JetBlue', '20', '35', '75', '125', 'Yikes']
grouped_airlines = []

# Iterate over the list in steps of 6 (each step = one airline's full data)
for idx in range(0, len(myList), 6):
    # Slice from current index to index + 6 to grab the complete airline entry
    airline_entry = myList[idx:idx+6]
    grouped_airlines.append(airline_entry)

More Concise List Comprehension #

If you prefer a shorter, cleaner way to achieve the same result, use a list comprehension:

myList = ['Southwest', '0', '0', '0', '0', 'Yes!', 'JetBlue', '20', '35', '75', '125', 'Yikes']
grouped_airlines = [myList[i:i+6] for i in range(0, len(myList), 6)]

Final Result #

After running either snippet, grouped_airlines will organize each airline’s data into its own sublist, exactly as you wanted:

[
    ['Southwest', '0', '0', '0', '0', 'Yes!'],
    ['JetBlue', '20', '35', '75', '125', 'Yikes']
]

This ensures every airline name stays paired with its 4 fees and descriptive phrase in a single, easy-to-access element.

内容的提问来源于stack exchange，提问作者Blake