如何捕获SOAPui发往Wiremock Server的XML报文并与XSD校验

嘿，我来帮你搞定这个问题！Wiremock其实有好几种实用的方式能捕获到SOAPui发过来的XML请求，之后对接XSD校验也没那么复杂，咱们一步步拆解来看：

Wiremock的核心能力就是通过存根匹配并记录请求，你可以创建一个存根来接收所有SOAP请求，同时把请求体保存下来：

• 如果你习惯用JSON配置存根，可以这么写：

  {
    "request": {
      "method": "POST",
      "urlPattern": "/your-soap-endpoint", // 匹配你的SOAP接口路径
      "headers": {
        "Content-Type": {
          "equalTo": "application/xml" // 指定XML类型的请求头，确保正确匹配
        }
      }
    },
    "response": {
      "status": 200,
      "body": "<soap:Envelope xmlns:soap=\"http://schemas.xmlsoap.org/soap/envelope/\"><soap:Body></soap:Body></soap:Envelope>" // 返回一个极简的SOAP响应即可
    },
    "recordRequest": true // 关键！开启请求记录开关
  }
  

• 要是用Java代码配置存根，写法是这样：

  stubFor(post(urlEqualTo("/your-soap-endpoint"))
          .withHeader("Content-Type", equalTo("application/xml"))
          .willReturn(aResponse().withStatus(200).withBody("<soap:Envelope xmlns:soap=\"http://schemas.xmlsoap.org/soap/envelope/\"><soap:Body></soap:Body></soap:Envelope>"))
          .withCaptureHeader("Content-Type", containing("application/xml")));
  

• 配置完成后，Wiremock会把捕获到的请求默认存在__files/mappings/requests目录下，你直接从这些文件里就能提取出XML请求体。

如果想要更灵活的处理（比如捕获请求后立刻做XSD校验），可以写一个Wiremock扩展，实现RequestListener接口：

• 先写一个自定义监听器，把捕获和校验逻辑整合进去：

  import com.github.tomakehurst.wiremock.core.Admin;
  import com.github.tomakehurst.wiremock.extension.Extension;
  import com.github.tomakehurst.wiremock.extension.PostServeAction;
  import com.github.tomakehurst.wiremock.http.Request;
  import com.github.tomakehurst.wiremock.http.Response;
  import javax.xml.XMLConstants;
  import javax.xml.transform.stream.StreamSource;
  import javax.xml.validation.Schema;
  import javax.xml.validation.SchemaFactory;
  import javax.xml.validation.Validator;
  import java.io.File;
  import java.io.StringReader;
  import java.nio.file.Files;
  import java.nio.file.Paths;
  
  public class XmlCaptureValidationExtension implements PostServeAction {
      private final SchemaFactory schemaFactory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
  
      @Override
      public String getName() {
          return "xml-capture-validation";
      }
  
      @Override
      public void doAction(Request request, Response response, Admin admin) {
          // 提取XML请求体
          String xmlBody = request.getBodyAsString();
          try {
              // 加载你的XSD文件
              Schema schema = schemaFactory.newSchema(new File("path/to/your/bookstore.xsd"));
              Validator validator = schema.newValidator();
              // 执行校验
              validator.validate(new StreamSource(new StringReader(xmlBody)));
              System.out.println("✅ XML请求符合XSD规范！");
              // 把捕获到的XML保存到本地文件
              Files.write(Paths.get("captured-soap-request.xml"), xmlBody.getBytes());
          } catch (Exception e) {
              System.err.println("❌ XML校验失败：" + e.getMessage());
          }
      }
  }
  

• 启动Wiremock的时候注册这个扩展：

  WireMockServer wireMockServer = new WireMockServer(options()
          .port(8080)
          .extensions(new XmlCaptureValidationExtension()));
  wireMockServer.start();
  

  这样每次SOAPui发请求过来，监听器都会自动捕获XML内容、完成XSD校验，还能把请求体保存到指定文件。

如果你只是想先批量捕获请求、之后再处理，Wiremock的录制功能会很省心：

• 用命令行启动Wiremock并开启录制模式（指定录制目录）：

  java -jar wiremock-jre8-standalone.jar --record-mappings --proxy-all="http://localhost:8080" --recorded-requests-dir="./captured-soap-requests"
  

• 接着用SOAPui往Wiremock发送请求，所有请求都会被录制下来，存到指定目录的JSON文件里，你直接从中提取XML请求体即可。

记得确保请求的Content-Type头是application/xml或者text/xml，这样Wiremock能正确识别并解析XML请求体，避免出现匹配失败或者解析错误的情况。

内容的提问来源于stack exchange，提问作者Matt