PostgreSQL如何选取多表指定列并将结果纵向合并
合并含'HESA'/'HEWH'表的geom与Name列结果
首先得给你提个小bug:你原来写的筛选列的条件COLUMN_NAME = 'geom' AND COLUMN_NAME = 'Name'是行不通的——一个列名不可能同时等于两个不同的值,得改成COLUMN_NAME IN ('geom', 'Name')或者用OR连接,才能正确找到包含这两列的表。
接下来要实现多表结果纵向合并,核心思路是动态生成UNION ALL拼接的查询语句,因为你的目标表是通过模糊匹配筛选出来的,没法硬写死。下面分步骤来:
1. 先确认同时包含geom和Name列的目标表
首先要确保每个目标表都同时有这两列,避免后续查询报错。执行这个语句找出符合要求的表:
SELECT DISTINCT TABLE_NAME FROM INFORMATION_SCHEMA.columns WHERE (TABLE_NAME LIKE '%HESA' OR TABLE_NAME LIKE '%HEWH') AND COLUMN_NAME IN ('geom', 'Name') GROUP BY TABLE_NAME HAVING COUNT(DISTINCT COLUMN_NAME) = 2;
这个查询会过滤掉只含其中一列的表,保证后续拼接的查询都能正常执行。
2. 动态生成合并查询语句
根据你用的数据库,选对应的写法:
如果你用PostgreSQL:
WITH target_tables AS ( SELECT DISTINCT TABLE_NAME FROM INFORMATION_SCHEMA.columns WHERE (TABLE_NAME LIKE '%HESA' OR TABLE_NAME LIKE '%HEWH') AND COLUMN_NAME IN ('geom', 'Name') GROUP BY TABLE_NAME HAVING COUNT(DISTINCT COLUMN_NAME) = 2 ) SELECT string_agg( format('SELECT geom, Name FROM %I', TABLE_NAME), ' UNION ALL ' ) AS union_query FROM target_tables;
执行后会得到一个完整的SELECT ... UNION ALL SELECT ...语句,复制这个结果直接执行,就能得到所有表的geom和Name列纵向合并的结果。
如果你用MySQL:
SELECT GROUP_CONCAT( CONCAT('SELECT geom, Name FROM `', TABLE_NAME, '`') SEPARATOR ' UNION ALL ' ) AS union_query FROM ( SELECT DISTINCT TABLE_NAME FROM INFORMATION_SCHEMA.columns WHERE (TABLE_NAME LIKE '%HESA' OR TABLE_NAME LIKE '%HEWH') AND COLUMN_NAME IN ('geom', 'Name') GROUP BY TABLE_NAME HAVING COUNT(DISTINCT COLUMN_NAME) = 2 ) AS target_tables;
同样,执行后拿到生成的拼接语句,直接运行就能得到合并后的结果。
其他数据库(比如SQL Server):
如果是SQL Server,可以用STRING_AGG或者FOR XML PATH来拼接,核心逻辑是一样的——先拿到目标表列表,再把每个表的查询语句用UNION ALL连起来。
举个SQL Server用STRING_AGG的例子:
WITH target_tables AS ( SELECT DISTINCT TABLE_NAME FROM INFORMATION_SCHEMA.columns WHERE (TABLE_NAME LIKE '%HESA' OR TABLE_NAME LIKE '%HEWH') AND COLUMN_NAME IN ('geom', 'Name') GROUP BY TABLE_NAME HAVING COUNT(DISTINCT COLUMN_NAME) = 2 ) SELECT STRING_AGG( CONCAT('SELECT geom, Name FROM ', QUOTENAME(TABLE_NAME)), ' UNION ALL ' ) AS union_query FROM target_tables;
最后一步
把上面生成的union_query结果复制出来,直接执行,就能得到所有符合条件的表中geom和Name列的纵向合并结果了。
内容的提问来源于stack exchange,提问作者Jscore
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