技术咨询：为何字符与整数相加（如‘G’+2）运行输出为73？

Great question! Let's walk through exactly what's happening here, since it boils down to how Java handles character and integer operations under the hood.

The Core Reason: Characters Are Integers in Java #

In Java, the char data type isn't just a "character" — it's actually a 16-bit unsigned integer that represents a Unicode (UTF-16) code point. When you perform arithmetic operations between a char and an int, Java automatically converts the char to its corresponding integer value first.

Step-by-Step Breakdown of the Operation #

Let's break down 'G' + 2 line by line:

• Convert the char to its integer value: The character 'G' corresponds to the Unicode code point 71 (you can remember this since 'A' is 65, so counting 6 steps forward gets you to 'G' at 71).
• Perform the integer addition: Now we're just adding two integers: 71 + 2 = 73.
• Print the result: System.out.println() takes this final integer value (73) and outputs it directly as a number.

Bonus: How to Get a Character Instead of a Number #

If you wanted the result to be the character corresponding to 73 (which is 'I') instead of the number, you'd need to explicitly cast the result back to a char:

System.out.println((char)('G' + 2)); // This outputs 'I'

内容的提问来源于stack exchange，提问作者Mados