如何用Python正则表达式拆分字符串中的数字与文本部分？

Got it, let's tackle this problem! You need a Python function that splits a string into alternating text and numeric elements—exactly like turning "this1is2a3string4" into ['this','1','is','2','a','3','string','4'] (I assume the "my" in your expected output was a typo for "a").

Here's a straightforward implementation using Python's re module:

import re

def my_func(string):
    # Match one or more digits OR one or more non-digits
    return re.findall(r'\d+|\D+', string)

# Test with your example input
print(my_func("this1is2a3string4"))
# Output: ['this', '1', 'is', '2', 'a', '3', 'string', '4']

How this works: #

• The regex pattern r'\d+|\D+' has two parts separated by | (which means "or"):
  • \d+: Matches one or more consecutive numeric characters
  • \D+: Matches one or more consecutive non-numeric characters
• re.findall() scans the entire input string, extracts all matching segments in order, and returns them as a list. This handles edge cases too—like strings starting/ending with numbers (e.g., "123hello456" becomes ['123', 'hello', '456']) or strings with no numbers at all.

If you need to handle empty strings or other edge cases, you can add a quick validation check, but for your core use case, this should work perfectly.

内容的提问来源于stack exchange，提问作者user6172474