如何对目录中的文件名排序并在文件名开头添加序号？附示例文件

Got it, let's solve this. You need to take all the video files in a specific folder, sort them logically, and prepend a sequential number to each filename—even if some already have numbers at the start. Here's a robust Python script that handles this, plus a walkthrough of how it works:

import os

def sort_and_rename_files(target_dir):
    # Define the video file extensions we want to process (case-insensitive)
    video_extensions = ('.MKV', '.MP4', '.mkv', '.mp4')
    
    # Grab all video files from the target directory
    video_files = [f for f in os.listdir(target_dir) if f.endswith(video_extensions)]
    
    # Custom sort key: strip leading numbers/punctuation to sort by the actual title
    def get_sort_key(filename):
        # Skip past any leading digits, dashes, dots, or spaces to get the core title
        for i, char in enumerate(filename):
            if not (char.isdigit() or char in '-., '):
                return filename[i:].lower()
        return filename.lower()
    
    # Sort the files using our custom key
    sorted_files = sorted(video_files, key=get_sort_key)
    
    # Rename each file with sequential numbering
    for idx, filename in enumerate(sorted_files, start=1):
        # Split filename into base name and extension
        name, ext = os.path.splitext(filename)
        
        # Clean up existing leading numbers/punctuation from the original name
        cleaned_name = name
        for i, char in enumerate(cleaned_name):
            if not (char.isdigit() or char in '-., '):
                cleaned_name = cleaned_name[i:]
                break
        
        # Create the new filename with the sequential number
        new_filename = f"{idx}-{cleaned_name}{ext}"
        old_path = os.path.join(target_dir, filename)
        new_path = os.path.join(target_dir, new_filename)
        
        # Avoid overwriting existing files by adding a counter if needed
        counter = 1
        while os.path.exists(new_path):
            new_filename = f"{idx}-{cleaned_name}_{counter}{ext}"
            new_path = os.path.join(target_dir, new_filename)
            counter += 1
        
        # Perform the rename and log the change
        os.rename(old_path, new_path)
        print(f"Renamed: {filename} -> {new_filename}")

# Replace this with your actual target directory path
target_directory = "/path/to/your/video/folder"
sort_and_rename_files(target_directory)

How This Works: #

• Target Directory: Swap out the target_directory value with the full path to your video folder.
• File Filtering: The script only processes .MKV and .MP4 files (works with both uppercase and lowercase extensions).
• Smart Sorting: The custom sort key ignores leading numbers, dashes, or dots, so files like 2.Kaggle Deep Learning - YouTube.MP4 and Kaggle Deep Learning 3 - YouTube.MP4 get grouped together correctly.
• Safe Renaming: If a new filename already exists (unlikely but possible), the script adds a counter suffix (e.g., _1, _2) to avoid overwriting files.
• Clean Titles: Existing leading numbers/punctuation are stripped from the original filename before adding the new sequential number, so you won't end up with messy names like 3-2.Kaggle Deep Learning....

Example Output: #

For your sample files, after running the script, you’ll get clean, numbered filenames like:

• 1-intro to deeplearning and computer vision.MKV
• 2-Kaggle Deep Learning - YouTube.MP4
• 3-Convolutional Neural Networks - Fun and Easy Machine Learning - YouTube.MP4
• 4-Convolutional Neural Networks - The Math of Intelligence (Week 4)YouTube.MKV
• 5-Introduction to Deep Learning- What Are Convolutional Neural Networks- YouTube.MP4
• 6-Kaggle Deep Learning 3 - YouTube.MP4
• 7-Kaggle Deep Learning 4 - YouTube.MP4
• 8-Kaggle Deep Learning 5 Data Augmentation - YouTube.MP4
• 9-Kaggle Deep Learning 6 - YouTube.MP4
• ...and so on for the rest of your files

Quick reminder: Always back up your files before running renaming scripts—better safe than sorry!

内容的提问来源于stack exchange，提问作者ryitesh