如何用JavaScript函数打印键为奇数的对象值？现有代码输出随机引用

嘿，我懂你要做的事了——你原本想让函数打印出对象里键为奇数的那些引用语句，但当前代码看起来是朝着随机输出的方向写的对吧？咱们来调整一下代码，达成你的目标。

首先先把你的引用对象补全（看起来最后一句没写完，我帮你补了个合理的收尾）：

const quotes = {
  0: "All computers wait at the same speed.",
  1: "A good programmer looks both ways before crossing a one-way street.",
  2: "Computers do not solve problems, they execute solutions.",
  3: "The best thing about a boolean is even if you are wrong, you are only off by a bit.",
  4: "Ubuntu is an ancient African word, meaning 'humanity to others'."
};

接下来分两种常见场景给你实现方案：

场景1：打印所有键为奇数的引用 #

如果要把所有键是奇数的引用全部打印出来，可以这么写：

function displayOddKeyQuotes() {
  const quotes = {
    0: "All computers wait at the same speed.",
    1: "A good programmer looks both ways before crossing a one-way street.",
    2: "Computers do not solve problems, they execute solutions.",
    3: "The best thing about a boolean is even if you are wrong, you are only off by a bit.",
    4: "Ubuntu is an ancient African word, meaning 'humanity to others'."
  };

  // 遍历对象所有键，筛选出奇数键并打印对应值
  Object.keys(quotes).forEach(key => {
    const numKey = parseInt(key);
    if (numKey % 2 !== 0) {
      console.log(quotes[key]);
    }
  });
}

// 调用函数执行
displayOddKeyQuotes();

运行后控制台会输出键为1和3的两句引用。

场景2：从奇数键的引用中随机选一个打印 #

如果你是想从所有奇数键的引用里随机挑一个输出（而不是全部），可以调整成这样：

function displayRandomOddQuote() {
  const quotes = {
    0: "All computers wait at the same speed.",
    1: "A good programmer looks both ways before crossing a one-way street.",
    2: "Computers do not solve problems, they execute solutions.",
    3: "The best thing about a boolean is even if you are wrong, you are only off by a bit.",
    4: "Ubuntu is an ancient African word, meaning 'humanity to others'."
  };

  // 先筛选出所有奇数键对应的引用，存入数组
  const oddQuotes = Object.entries(quotes)
    .filter(([key]) => parseInt(key) % 2 !== 0)
    .map(([_, quote]) => quote);

  // 有符合条件的引用就随机选一个打印，否则提示无结果
  if (oddQuotes.length > 0) {
    const randomIndex = Math.floor(Math.random() * oddQuotes.length);
    console.log(oddQuotes[randomIndex]);
  } else {
    console.log("没有找到键为奇数的引用");
  }
}

// 调用函数执行
displayRandomOddQuote();

关键逻辑说明： #

• 用Object.keys()或Object.entries()遍历对象的键值对，能完整拿到所有键信息
• 把字符串类型的键转成数字（对象的键默认是字符串），再用numKey % 2 !== 0判断是否为奇数
• 随机选择的逻辑是先收集符合条件的引用到数组，再用Math.random()生成随机索引

内容的提问来源于stack exchange，提问作者Bala Hantsi