Ubuntu+Asterisk环境下使用Pycall调用出现验证错误求助
Hey there! Let's work through this Pycall validation error you're facing. Since your Asterisk setup is already working smoothly with Zoiper, the issue is likely tied to how Pycall interacts with Asterisk's configuration, permissions, or syntax requirements. Here are the key steps to diagnose and fix this:
1. Check Spool Directory Permissions
Pycall needs write access to Asterisk's outgoing spool directory (default: /var/spool/asterisk/outgoing/) to drop the call file.
- First, verify the directory's permissions with:
ls -ld /var/spool/asterisk/outgoing/ - If your user account doesn't have write access, add yourself to the
asteriskgroup for a persistent fix:
Log out and back in for this change to take effect. Alternatively, temporarily grant world write access for quick testing:sudo usermod -aG asterisk your_usernamesudo chmod o+w /var/spool/asterisk/outgoing/
2. Validate Your Call Target Format
The SIP/flowroute/18882223333 target must match Asterisk's expected channel syntax and your SIP trunk configuration.
- Test the call directly from the Asterisk console first to rule out trunk issues:
- Enter the Asterisk console:
asterisk -rvvv - Run this command to initiate the call manually:
channel originate SIP/flowroute/18882223333 application Playback hello-world
- Enter the Asterisk console:
- If this command fails, check your
sip.confto ensure theflowroutepeer is correctly defined, and the number format matches your trunk's requirements. If it works, the issue is specific to Pycall's configuration.
3. Capture Detailed Pycall Error Messages
Generic "validation error" messages aren't helpful—let's get specifics by wrapping your code in a try-except block:
from pycall import CallFile, Call, Application try: call = Call('SIP/flowroute/18882223333') action = Application('Playback', 'hello-world') c = CallFile(call, action) c.spool() except Exception as e: print(f"Full error details: {str(e)}")
This will tell you exactly what's failing (e.g., missing required parameters, permission denied, invalid channel syntax).
4. Verify Pycall-Asterisk Compatibility
Pycall versions can have compatibility gaps with older Asterisk releases like 13.20.
- Upgrade Pycall to the latest version to rule out version-specific bugs:
pip install --upgrade pycall - If upgrading doesn't help, try explicitly adding required parameters to the
Callobject (some older Pycall versions expect these):call = Call('SIP/flowroute/18882223333', context='default', extension='18882223333')
5. Test with a Manual Call File
Pycall works by generating a call file and dropping it into the spool directory. Let's bypass Pycall entirely to confirm Asterisk can process the call:
- Create a file named
test.callwith this content:Channel: SIP/flowroute/18882223333 Application: Playback Data: hello-world - Move it to the spool directory:
sudo mv test.call /var/spool/asterisk/outgoing/ - Check if the call initiates, and monitor Asterisk's logs for issues:
tail -f /var/log/asterisk/messages
If this manual call works, the problem is definitely in Pycall's setup; if not, debug your Asterisk trunk or dialplan further.
内容的提问来源于stack exchange,提问作者user9315259

