PHP中如何显示下个月日期？现有代码无法得到预期结果求助

Let's break down what's wrong with your code and how to fix it to get the desired output of 2018-03-15.

Issues in the Original Code #

• Incorrect format string in date(): You passed '$date' as the first argument to date(), but this function expects a format specifier (like 'Y-m-d') to define how the date should be formatted.
• Syntax error: Missing closing parenthesis ) for the strtotime() call.
• Relative date reference: strtotime('+1 month') adds a month to the current date by default, not your specified $date. You need to base the calculation on your input date.

Corrected Code #

Here's the fixed version that will output 2018-03-15:

$date = "2018-02-15";
// Convert the original date to a timestamp, then add 1 month
$next_month_timestamp = strtotime('+1 month', strtotime($date));
// Format the timestamp to the desired 'Y-m-d' format
$next_month = date('Y-m-d', $next_month_timestamp);
echo $next_month; // Outputs: 2018-03-15

Simplified Version #

You can also combine the steps into a single line if you prefer:

$date = "2018-02-15";
$next_month = date('Y-m-d', strtotime('+1 month', strtotime($date)));
echo $next_month;

How It Works #

1. strtotime($date) converts your input string 2018-02-15 into a Unix timestamp (a numeric representation of the date).
2. strtotime('+1 month', $original_timestamp) takes that timestamp and adds one month to it, returning a new timestamp for 2018-03-15.
3. date('Y-m-d', $new_timestamp) formats the new timestamp back into the YYYY-MM-DD string format you need.

Edge Case Consideration #

Note that if your input date is the last day of a month (e.g., 2020-02-29), strtotime('+1 month') will handle it intelligently (returning 2020-03-29 instead of an invalid date). If you want to always get the last day of the next month, you could use strtotime('last day of next month', strtotime($date)) instead.

内容的提问来源于stack exchange，提问作者Richard Alex