Python列表元组元素替换求助：将词性为NN的词替换为'NN'

Hey there! I've got you covered. The key here is to iterate through each tuple in your list, check if the part-of-speech (POS) tag is NN, and replace the corresponding word with NN when that condition is met.

Using List Comprehension (Concise, Pythonic Approach) #

This is the most efficient way to handle this task—it's short and easy to read once you're familiar with list comprehensions:

# Your original data list
original_data = [('The', 'NNP'), ('map', 'NNP'), ('is', 'VBZ'), ('way', 'NN'), ('of', 'IN'), ('using', 'VBG'), ('tool', 'NN'), (',', ','), ('skill', 'VBG'), ('and', 'CC')]

# Modify the list with conditional logic in a comprehension
modified_data = [('NN', pos) if pos == 'NN' else (word, pos) for word, pos in original_data]

# Print the final result
print(modified_data)

Using a For Loop (Beginner-Friendly, Explicit Approach) #

If you prefer to break down each step for clarity, a basic for loop works just as well:

original_data = [('The', 'NNP'), ('map', 'NNP'), ('is', 'VBZ'), ('way', 'NN'), ('of', 'IN'), ('using', 'VBG'), ('tool', 'NN'), (',', ','), ('skill', 'VBG'), ('and', 'CC')]
modified_data = []

for word, pos in original_data:
    # Check if the POS tag matches 'NN'
    if pos == 'NN':
        modified_data.append(('NN', pos))
    else:
        # Keep the original tuple unchanged
        modified_data.append((word, pos))

print(modified_data)

Expected Output #

Both methods will generate exactly the output you need:

[('The', 'NNP'), ('map', 'NNP'), ('is', 'VBZ'), ('NN', 'NN'), ('of', 'IN'), ('using', 'VBG'), ('NN', 'NN'), (',', ','), ('skill', 'VBG'), ('and', 'CC')]

内容的提问来源于stack exchange，提问作者Steve DEU