Python 3.6.5统计字母时遇TypeError: 'int' object is not iterable如何修复？

Hey there, let's break down what's going wrong and fix your code step by step.

The Root Cause of the Error #

That TypeError: 'int' object is not iterable is coming from this line:

for i in h:

You set h = len(line) which gives you an integer (the length of the current line). But for loops need an iterable object (like a string, list, or tuple) to loop through—you can't loop over a single integer, hence the error.

On top of that, your character check was off: if line == "a" or line == "A" was comparing the entire line to a single character, which would never be true. You need to check each individual character instead.

Corrected Code #

Here's the fixed version that will count all 'a' and 'A' characters correctly:

x = 0
f = open('in_a.txt', encoding='utf-8')
for line in f:
    # Loop through each character in the current line directly
    for char in line:
        if char == "a" or char == "A":
            x += 1
print("this document has %d A or a characters" % (x))

Key Changes Made #

• Removed h = len(line) and the invalid for i in h loop—instead, we iterate directly over the line string (strings are iterable, so we can loop through each character one by one)
• Changed line to char in the condition check, so we're verifying each single character instead of the whole line
• Tweaked "documents" to "document" for grammatical accuracy

When you run this with your test text, it will output exactly what you expect: this document has 10 A or a characters.

内容的提问来源于stack exchange，提问作者Crazy coding kid