实现逗号分隔字符串中连续相同值的分组计数格式化

Alright, let's tackle this problem where you need to group consecutive identical elements from a comma-separated string and format each group as [element] x[count]. Here's a straightforward way to do this using Python:

Example Input & Output #

Input string: "paid,paid,paid,paid,unpaid,paid,paid,paid,paid,unpaid,unpaid,unpaid,paid,paid,Pinterest,unpaid,Pinterest,unpaid,unpaid"
Expected output: "paid x4, unpaid x1, paid x4, unpaid x3, paid x2, Pinterest x1, unpaid x1, Pinterest x1, unpaid x2"

Solution Code #

def group_consecutive_elements(input_str):
    # Split the input string into individual elements
    elements = input_str.split(',')
    if not elements:
        return ""
    
    result = []
    # Start tracking the first element and its count
    current_element = elements[0]
    count = 1
    
    # Iterate through the rest of the elements
    for elem in elements[1:]:
        if elem == current_element:
            count += 1
        else:
            # Add the completed group to the result
            result.append(f"{current_element} x{count}")
            # Reset tracking to the new element
            current_element = elem
            count = 1
    # Don't forget to add the final group after the loop ends
    result.append(f"{current_element} x{count}")
    
    # Join all groups into the final formatted string
    return ', '.join(result)

# Test with your input data
input_str = "paid,paid,paid,paid,unpaid,paid,paid,paid,paid,unpaid,unpaid,unpaid,paid,paid,Pinterest,unpaid,Pinterest,unpaid,unpaid"
print(group_consecutive_elements(input_str))

How It Works #

1. Split the Input: We first break the comma-separated string into a list of individual elements to iterate over.
2. Track Consecutive Elements: We keep track of the current element we're counting and how many times it's appeared consecutively.
3. Build Groups: As we loop through elements, we increment the count if the element matches the current tracked one. When we hit a new element, we format the existing group and add it to our result list, then reset our tracker.
4. Final Group Handling: After the loop finishes, we add the last remaining group (since the loop won't trigger the group addition for the final set of elements).
5. Format Output: Finally, we join all the formatted groups back into a single comma-separated string.

This logic is easy to adapt to other languages too—just replicate the "track current element + count consecutive matches" pattern!

内容的提问来源于stack exchange，提问作者Hound