C#正则表达式：匹配含等号且无逗号、嵌套括号的方括号内容

Hey there! Let's adjust your regex to meet that requirement—here's how to do it:

Solution #

To modify your existing regex so it only matches square brackets containing at least one = (while still excluding commas and nested brackets), use this pattern:

\[([^,\[\]]*=[^,\[\]]*)\]

How It Works #

Let's break down the parts to see what changed from your original regex:

• \[ and \]: Still match the opening and closing square brackets literally, just like before.
• ([^,\[\]]*=[^,\[\]]*): This is the updated capturing group for the content inside the brackets:
  • [^,\[\]]*?: Matches zero or more non-greedy characters that aren't commas, opening brackets, or closing brackets. This covers any text before the =.
  • =: The mandatory equals sign—this ensures we only match brackets that have at least one = inside.
  • [^,\[\]]*?: Matches zero or more non-greedy characters that aren't commas, opening brackets, or closing brackets. This covers any text after the =.

Edge Cases & Adjustments #

If you want to disallow cases where the = is at the very start or end of the bracket content (like [=Test] or [Test=]), you can tweak the regex to require at least one character on both sides of the =:

\[([^,\[\]]+=[^,\[\]]+)\]

Test Cases #

Let's verify this works with your examples and other scenarios:

• ✅ Matches: [Test=Test] → captures Test=Test
• ✅ Matches: [Test=Test;Test2=Test2] → captures Test=Test;Test2=Test2
• ❌ Doesn't match: [NoEquals] (no =)
• ❌ Doesn't match: [Has,Comma=Test] (contains comma)
• ❌ Doesn't match: [Nested[Brackets]=Test] (nested brackets)

That should cover exactly what you need!

内容的提问来源于stack exchange，提问作者LordCaos