正则表达式实现内容定位与跨位置替换需求咨询

Got it, let's solve this regex replacement task together. You've already started matching the relevant parts, now we just need to combine those pieces into a single pattern that captures the value we need and places it exactly where it belongs.

Step 1: The Find Pattern #

We'll use a regex that captures key segments of your string to rearrange later. Here's the pattern:

(<parameter[^>]*type=")(".*?>)\\type{([^}]*)}(.*)

Let's break down each component:

• (<parameter[^>]*type="): Capture Group 1 – grabs everything from the start of the <parameter> tag up to the opening quote of the empty type attribute.
• ": Matches the closing quote of the empty type attribute (we don't capture this because we're replacing its position with our extracted value).
• (.*?>): Capture Group 2 – captures the rest of the <parameter> tag from the closing quote to the tag's end (>). The .*? is a non-greedy match to avoid overshooting into unrelated content.
• \\type{: Matches the literal \type{ (we escape the backslash with another backslash since it’s a special regex character).
• ([^}]*): Capture Group 3 – grabs the value inside the curly braces (like INT in your example) by matching any character except }.
• }(.*): Capture Group 4 – captures the closing } and everything that comes after it in the string.

Step 2: The Replacement String #

Now we’ll rearrange the captured groups to plug the extracted value into the empty type attribute. Use this replacement string:

$1$3$2$4

Here's what each part does:

• $1: Puts back the first captured group (<parameter ... type=").
• $3: Inserts the value we extracted from \type{...} (like INT).
• $2: Adds back the rest of the <parameter> tag (from the closing quote to >).
• $4: Appends the remaining content of the string (minus the original \type{INT} part, which we’ve moved).

Example Result #

Applying this to your sample string:

Original: <parameter name="some name" value="VALU" type="" perm="" ncpv="1"><doc></doc></parameter> \type{INT}\ro some documentation

After replacement: <parameter name="some name" value="VALU" type="INT" perm="" ncpv="1"><doc></doc></parameter> \ro some documentation

Optional: Keep the Original \type{INT} #

If you want to copy the value instead of moving it (leaving \type{INT} in the string), use this replacement string instead:

$1$3$2\\type{$3}$4

This will retain the original \type{INT} while still filling the type attribute with the same value.

内容的提问来源于stack exchange，提问作者user3270371