关于2019 CE认证LTS版本要求及Build 11等版本的技术问询

Hey there! Let’s unpack your questions about Cobalt LTS versions and 2019 CE certification requirements clearly:

Key Questions Answered #

1. Is Build 11 an LTS release? #

Based on Cobalt’s official release practices tied to 2019 CE compliance:

• The Cobalt 2019 LTS is the baseline long-term support release required for meeting 2019 CE certification rules.
• Build 11 qualifies as an LTS-compliant build if it’s part of the 2019 LTS release train—meaning it’s a maintenance update (bug fixes, security patches) rolled out under the 2019 LTS branch. Cobalt often uses build numbers for incremental updates within an LTS cycle, so if Build 11 is associated with the 2019 LTS stream, it meets the "no earlier than Cobalt 2019 LTS" requirement.
• If Build 11 were a standalone non-LTS feature release outside the 2019 LTS branch, it would not count as an LTS version (even if it’s newer).

2. Will all subsequent versions be LTS releases? #

No, this is not the case. Cobalt follows a standard release model that balances long-term support and feature innovation:

• LTS branches: Periodically designated (e.g., annual) branches that get multi-year support, security patches, and compliance updates. Future LTS releases (like Cobalt 2020 LTS, 2021 LTS, etc.) will exist, but they’re separate from non-LTS builds.
• Non-LTS feature releases: These are interim builds that introduce new functionality but don’t receive long-term support. They won’t qualify as LTS versions, even if they’re released after the 2019 LTS.
• Maintenance builds for existing LTS branches: Any future updates to the 2019 LTS branch (e.g., Build 12, 13 for 2019 LTS) will still be considered LTS-compliant.

Quick CE Certification Note #

For your 2019 CE certification, you only need to ensure your device runs a version that’s at least the initial Cobalt 2019 LTS release, or any maintenance build within the 2019 LTS branch. Newer non-LTS releases don’t automatically meet the LTS requirement for 2019 CE.

内容的提问来源于stack exchange，提问作者Eduard Kegulskiy