JavaScript通过类获取值：批量检测网站状态的实现疑问

Hey there! Let's work through this together—you’re already on the right track by using a class to wrap your site-checking logic, which is perfect for reusability. Here’s how you can adapt your script to batch-check those 3 sites from your table:

Step 1: Make Sure Your Class is Ready for Reuse #

First, let’s assume your existing SiteChecker class looks something like this (adjust if your code differs):

import requests

class SiteChecker:
    def __init__(self, url):
        self.url = url
        self.status = None

    def check_status(self):
        """Check if the site is up and update its status"""
        try:
            # Add a timeout to avoid hanging on unresponsive sites
            response = requests.get(self.url, timeout=5)
            # Raise an error for HTTP status codes like 404/500
            response.raise_for_status()
            self.status = f"✅ {self.url} is online! Status code: {response.status_code}"
        except requests.exceptions.RequestException as e:
            self.status = f"❌ {self.url} is offline. Error: {str(e)}"

    def get_status(self):
        """Return the site's status (runs check if not already done)"""
        if self.status is None:
            self.check_status()
        return self.status

This class encapsulates all the logic for checking a single site—perfect for reusing across multiple URLs.

Step 2: Extract URLs from Your Table #

If your table is HTML, you can pull the URLs out using a parser like BeautifulSoup (install it first with pip install beautifulsoup4 if you haven’t):

from bs4 import BeautifulSoup

# Replace this with your actual table HTML snippet
table_html = """
<table>
    <thead>
        <tr>
            <th>Site Name</th>
            <th>URL</th>
        </tr>
    </thead>
    <tbody>
        <tr>
            <td>Example Site 1</td>
            <td><a href="https://example.com">example.com</a></td>
        </tr>
        <tr>
            <td>Test Site 2</td>
            <td><a href="https://test.com">test.com</a></td>
        </tr>
        <tr>
            <td>Demo Site 3</td>
            <td><a href="https://demo.com">demo.com</a></td>
        </tr>
    </tbody>
</table>
"""

# Parse the HTML to get all site URLs
soup = BeautifulSoup(table_html, "html.parser")
site_urls = []
for row in soup.find("tbody").find_all("tr"):
    # Grab the href attribute from the link in each row
    url = row.find("a")["href"]
    site_urls.append(url)

If you already have the URLs handy, you can skip parsing and just define them as a list directly:

site_urls = [
    "https://example.com",
    "https://test.com",
    "https://demo.com"
]

Step 3: Batch Check All Sites #

Now it’s easy to loop through your list of URLs and use your class to check each one:

# Loop through each URL and print its status
for url in site_urls:
    checker = SiteChecker(url)
    print(checker.get_status())

Bonus: Lightweight Class Method Alternative #

If you don’t need to store extra data for each site (like check history), you can turn the check into a class method to avoid creating instances:

class SiteChecker:
    @classmethod
    def check_site(cls, url):
        try:
            response = requests.get(url, timeout=5)
            response.raise_for_status()
            return f"✅ {url} is online! Status code: {response.status_code}"
        except requests.exceptions.RequestException as e:
            return f"❌ {url} is offline. Error: {str(e)}"

# Batch check with the class method
for url in site_urls:
    print(SiteChecker.check_site(url))

Quick Tips #

• Save results: Instead of printing, store statuses in a list/dictionary to write back to a CSV/table later.
• Concurrent checks: For faster results with more sites, use concurrent.futures.ThreadPoolExecutor to check multiple sites at once (great for larger batches).
• Error handling: Adjust the exception types if you want to catch specific issues (like DNS failures vs. timeouts) separately.

内容的提问来源于stack exchange，提问作者Berglund