NumPy代码中X[y == label].sum(axis=0)语法理解咨询
counts[label] = X[y == label].sum(axis=0) in Your Code Hey there! Let's break down this line piece by piece so you can see exactly how it works with your sample data.
Step 1: Boolean Indexing with y == label
In NumPy, when you use a boolean array to index a 2D array (like your X), it acts as a row filter: it selects only the rows where the boolean value is True.
For example, when label = 1, y == label gives you the boolean array [False, True, False, True]. Applying this to X (X[y == label]) will pull out the rows of X that correspond to True positions—so rows 1 and 3:
# X[y == 1] results in: array([[1, 0, 1, 1], [1, 0, 1, 0]])
Step 2: Summing Along Columns with .sum(axis=0)
The .sum(axis=0) method calculates the sum vertically, across columns (instead of horizontally across rows, which would be axis=1).
Using the subset above, summing each column gives:
- Column 0:
1 + 1 = 2 - Column 1:
0 + 0 = 0 - Column 2:
1 + 1 = 2 - Column 3:
1 + 0 = 1
So the result is array([2, 0, 2, 1]), which gets stored as counts[1].
Step 3: Putting It All Together for Both Labels
When label = 0, y == label gives [True, False, True, False]. Filtering X gives rows 0 and 2:
# X[y == 0] results in: array([[0, 1, 0, 1], [0, 0, 0, 1]])
Summing these columns gives array([0, 1, 0, 2]), stored as counts[0].
Final Result
After the loop runs, your counts dictionary will look like this:
{0: array([0, 1, 0, 2]), 1: array([2, 0, 2, 1])}
Each value is the total number of times each feature (column) appears as non-zero in samples belonging to that label.
内容的提问来源于stack exchange,提问作者Samarth Upadhyaya

