Python正则匹配：捕获以TASK开头且含.retry结尾的多段分组

Got it, let's fix your regex to precisely catch only the failed TASK blocks (those ending with .retry) without picking up the successful ones. Here's how to do it:

Final Regex Pattern #

TASK \*{30,}(?:(?!TASK \*{30,}).)*?\.retry

Breakdown of the Pattern #

Let's walk through each part so you understand how it works:

• TASK \*{30,}: Matches the start of a TASK block, including the TASK keyword and the long string of asterisks. The {30,} ensures we match at least 30 asterisks (adjust this number if your actual TASK markers have more or fewer stars—you could also use \*+ for one or more asterisks if the exact count doesn't matter).
• (?:(?!TASK \*{30,}).)*?: This is the key part that prevents cross-block matching. The negative lookahead (?!TASK \*{30,}) checks that the next character isn't the start of a new TASK block. The .*? is a non-greedy match, meaning it stops as soon as it hits the .retry at the end of the failed block.
• \.retry: Matches the exact failure marker at the end of the block. We escape the dot with \ because dots have special meaning in regex (they match any character).

Handling Multiline TASK Blocks #

If your TASK blocks include line breaks, add the DOTALL flag (or (?s) at the start of the regex) so the . matches newline characters too:

(?s)TASK \*{30,}(?:(?!TASK \*{30,}).)*?\.retry

Test with Your Example Text #

When run against your sample string:

TASK ********************************** everything ok TASK ********************************** some text here until you get dot retry.retry TASK ********************************** everything ok

This regex will only capture the failed block:
TASK ********************************** some text here until you get dot retry.retry

内容的提问来源于stack exchange，提问作者Mazimer