Python重复单词检测代码报错求助：实现单词唯一性判定功能

Let's work through fixing your code step by step—there are several syntax and logic issues causing the error you're seeing:

• The isUnique() function doesn't accept any arguments, but you're passing user_input when calling it. You need to add a parameter to capture the input sentence.
• You're using sentence.split() but sentence isn't defined anywhere—this should reference the function's input parameter instead.
• In the for loop, you're iterating over i but checking if word not in unique (typo: word should be i).
• You're mixing up variable names: count[i] is used but count was never initialized, while you meant to update the unique dictionary.
• Python uses capitalized boolean values (True/False), not lowercase true/false.
• Your function doesn't return anything—so when you assign uniques = isUnique(user_input), it will always be None.
• The logic for detecting duplicates is reversed: you want to flag duplicates, not mark uniqueness in a dictionary.

Here's a simplified, corrected version of your code that meets your requirements:

def is_unique(sentence):
    words = sentence.split()
    # Sets automatically remove duplicates—compare lengths to check for repeats
    if len(words) != len(set(words)):
        return "not unique"
    else:
        return "unique"

def main():
    user_input = input("Enter words separated by space: ")
    result = is_unique(user_input)
    print(result)

main()

Quick Explanation: #

• Renamed isUnique to is_unique to follow Python's standard snake_case naming convention (optional but recommended for readability).
• Added a sentence parameter to the function so it can receive the user's input.
• Used a set to efficiently check for duplicates: since sets can't hold duplicate values, if the length of the word list doesn't match the set length, duplicates exist.
• Fixed the typo in the input prompt ("sperated" → "separated").
• Added clear return statements that directly output your required strings.

If you want to stick with a dictionary-based approach to understand the iteration logic better, here's a corrected version using that method:

def is_unique(sentence):
    words = sentence.split()
    seen_words = {}
    for word in words:
        if word in seen_words:
            # Return immediately when a duplicate is found (more efficient)
            return "not unique"
        seen_words[word] = True
    # If we finish the loop without finding duplicates
    return "unique"

def main():
    user_input = input("Enter words separated by space: ")
    result = is_unique(user_input)
    print(result)

main()

This version tracks words we've already seen in a dictionary, and exits early as soon as a duplicate is detected—saving unnecessary iterations if a repeat shows up early in the sentence.

内容的提问来源于stack exchange，提问作者filedelete