调用unlockMaterial函数时数组参数materialCosts为何返回undefined?
materialCosts array parameter return undefined in the function call? I'm calling the function unlockMaterial('Ore', 0, ['money', 100]) with the following definition:
function unlockMaterial (material, index, materialCosts) { console.log(material) console.log(index) console.log(materialCosts) }
But the console outputs Ore 0 undefined. I can't figure out why the materialCosts array is coming through as undefined. For context, I plan to use a similar call pattern later for another function: craftItem(material, array).
Let's break down the possible reasons why your materialCosts parameter is showing up as undefined—your initial function definition and call look syntactically correct, so this is likely a hidden issue in your code:
1. Your function was redefined elsewhere with fewer parameters
It’s common to accidentally overwrite a function later in your code. If somewhere after the original unlockMaterial definition, you have another version that only accepts 2 parameters, that’s the one being executed:
// This later definition replaces the original function unlockMaterial(material, index) { console.log(material); console.log(index); console.log(materialCosts); // materialCosts isn't a parameter here, so it's undefined }
To verify this, log the function’s source code right before your call:
console.log(unlockMaterial.toString());
This will show you the actual function definition that’s being used.
2. A typo or hidden error in your function call
Double-check the line where you call unlockMaterial:
- Did you accidentally omit the third parameter entirely? (e.g.,
unlockMaterial('Ore', 0)instead of including the array) - Is the array being passed as a variable that’s accidentally set to
undefined? (e.g.,const costs = undefined; unlockMaterial('Ore', 0, costs)) - Did you use invalid syntax for the array? (Like Chinese brackets
【】instead of square brackets[]—though this would throw a syntax error, so your code wouldn’t run at all if this were the case)
3. The parameter is being shadowed inside the function
If you have a variable named materialCosts defined inside the function, it will overwrite the input parameter:
function unlockMaterial (material, index, materialCosts) { let materialCosts = undefined; // This shadows the input parameter console.log(material); console.log(index); console.log(materialCosts); // Logs the internal undefined variable, not the input }
Scan the function body for any declarations of materialCosts that might be causing this conflict.
For your upcoming craftItem call
Keep these same checks in mind:
- Confirm the
craftItemfunction accepts the number of parameters you’re passing - Avoid redefining the function later in your code
- Make sure no internal variables shadow the
arrayparameter
内容的提问来源于stack exchange,提问作者bejewelled

