如何读取用户输入字符串并按格式输出单个字符？附Java代码

Got it, let's fix up your code to meet the requirement: splitting each character with commas, and using multiple spaces (or   as shown in your example) between words. Here's the complete, working implementation with explanations:

Complete Java Code #

import java.util.Scanner;

public class A {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        System.out.println("Enter any String:");
        String name = sc.nextLine();
        System.out.println("Before Splited: " + name);
        
        // Use StringBuilder for efficient string concatenation
        StringBuilder formattedResult = new StringBuilder();
        
        for (int i = 0; i < name.length(); i++) {
            char currentChar = name.charAt(i);
            
            if (currentChar == ' ') {
                // Add two non-breaking spaces (matches your example's &nbsp;&nbsp;)
                formattedResult.append("&nbsp;&nbsp;");
            } else {
                // Convert to lowercase to match your example's output (remove if not needed)
                formattedResult.append(Character.toLowerCase(currentChar));
                
                // Only add comma if it's not the last character, and next char isn't a space
                if (i != name.length() - 1 && name.charAt(i + 1) != ' ') {
                    formattedResult.append(",");
                }
            }
        }
        
        System.out.println("After Formatted: " + formattedResult);
        sc.close();
    }
}

Key Logic Breakdown #

• Efficient String Building: We use StringBuilder instead of repeated String concatenation because it's faster and uses less memory, especially for longer strings.
• Word Separation Handling: When we hit a space (word boundary), we append two   (if you need console output instead of HTML, replace this with two regular spaces ).
• Character & Comma Placement:
  • Each non-space character is converted to lowercase (to match your example's j,a,v,a instead of J,a,v,a — remove Character.toLowerCase() if you want to keep original case).
  • We only add a comma if:
    1. It's not the very last character in the string.
    2. The next character isn't a space (so we don't add a comma right before a word separator).

Example Test Run #

If you input:

Java is one of the most popular language

The output will be:

j,a,v,a   i,s   o,n,e   o,f   t,h,e   m,o,s,t   p,o,p,u,l,a,r   l,a,n,g,u,a,g,e

Quick Adjustments #

• Keep original character case: Remove Character.toLowerCase() from the code.
• Console-friendly spacing: Replace "  " with " " (two regular spaces).

内容的提问来源于stack exchange，提问作者Amit Singh