如何基于字符串名称返回元胞数组？附分析所得示例元胞数组A

Hey there! Based on your example cell array A, here are a few straightforward ways to retrieve the corresponding cell(s) using the name string:

1. Exact Match with Vectorized Lookup (Most Efficient) #

If you need an exact match for the name string, use strcmp to create a logical index, then index into A:

% Define the target name you're looking for
targetName = 'Upper_lower_torque/REV--Lower torque.1';

% Create logical index where the first element of each cell matches targetName
matchIdx = strcmp(cellfun(@(x) x{1}, A), targetName);

% Get the matching cell(s)
matchingCells = A(matchIdx);

How this works: #

• cellfun(@(x) x{1}, A) extracts all the name strings from the first position of each cell in A.
• strcmp(..., targetName) compares each extracted string to your target, returning a boolean array where true means a match.
• A(matchIdx) pulls out all cells that match the target name.

2. Simple Loop (Great for Beginners) #

If you prefer a more explicit approach, loop through each element in A and check for matches:

targetName = 'Upper_lower_torque/SPH-Lower torque-Upper torque.1';
matchingCells = {};

for i = 1:length(A)
    if strcmp(A{i}{1}, targetName)
        matchingCells{end+1} = A{i};
    end
end

This builds a new cell array matchingCells containing all elements where the name matches your target.

3. Partial Match (If You Don't Need Exact Strings) #

If you want to find all cells where the name contains a specific substring, use contains instead of strcmp:

targetSubstring = 'Lower torque';
matchIdx = contains(cellfun(@(x) x{1}, A), targetSubstring);
matchingCells = A(matchIdx);

This will return both elements from your example, since both names include "Lower torque".

Notes: #

• If multiple cells match your target, matchingCells will be a cell array of all those matches. If only one matches, it'll be a 1x1 cell array (you can access the force/torque data with matchingCells{1}{3}).
• Always check isempty(matchingCells) to handle cases where no matches are found and avoid errors.

内容的提问来源于stack exchange，提问作者Ruben