Java中如何截取字符串特定部分？提取VIN段内容至List<String>

Alright, let's solve this string extraction problem. You need to pull the VIN codes (from A9 to Z5 in your example) into a List<String>, and since the codes themselves can change but the VIN and CODES markers are fixed, we can use pattern-based approaches that don't rely on hardcoding the codes. Here are two reliable methods, using Java as the example language since you mentioned List<String>:

Method 1: Regular Expressions (Flexible for Variable Formatting) #

Regex is great here because it can handle minor variations in spacing around the markers. We'll create a pattern that captures everything between VIN : and the next - CODES : segment, then split that captured content into individual codes.

import java.util.ArrayList;
import java.util.List;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class VinCodeExtractor {
    public static void main(String[] args) {
        String input = "- VIN : A9 C1 C4 C5 C6 E9 F2 F5 F8 G1 G7 H4 H6 I1 I4 I5 I6 I7 J1 K8 L3 L5 M4 O2 P6 Q9 R3 S3 T9 U3 V2 V3 V9 W5 Z5 - CODES : A9 C1 C4 C5 C6 E9 F2 F5 F8 G1 G7 H4 H6 I1 I4 I5 I6 I7 J1 K8 L3 L5 M4 O2 P6 Q9 R3 S3 T9 U3 V2 V3 V9 W5 Y4 Y8";
        
        // Regex pattern to capture the VIN section between the fixed markers
        Pattern vinPattern = Pattern.compile("VIN : (.*?) - CODES :");
        Matcher matcher = vinPattern.matcher(input);
        
        List<String> vinCodes = new ArrayList<>();
        if (matcher.find()) {
            // Get the full VIN code string
            String vinSection = matcher.group(1);
            // Split by one or more spaces, trim to avoid empty strings
            String[] codeArray = vinSection.trim().split("\\s+");
            for (String code : codeArray) {
                vinCodes.add(code);
            }
        }
        
        // Output the result
        System.out.println("Extracted VIN Codes: " + vinCodes);
    }
}

Method 2: String Splitting (Simple for Well-Formatted Input) #

If your input string always follows the exact structure you shared, splitting the string directly on the fixed markers is straightforward and easy to read.

import java.util.ArrayList;
import java.util.List;

public class VinCodeExtractorSplit {
    public static void main(String[] args) {
        String input = "- VIN : A9 C1 C4 C5 C6 E9 F2 F5 F8 G1 G7 H4 H6 I1 I4 I5 I6 I7 J1 K8 L3 L5 M4 O2 P6 Q9 R3 S3 T9 U3 V2 V3 V9 W5 Z5 - CODES : A9 C1 C4 C5 C6 E9 F2 F5 F8 G1 G7 H4 H6 I1 I4 I5 I6 I7 J1 K8 L3 L5 M4 O2 P6 Q9 R3 S3 T9 U3 V2 V3 V9 W5 Y4 Y8";
        
        List<String> vinCodes = new ArrayList<>();
        
        // Split to isolate the part after "VIN : "
        String postVin = input.split("- VIN : ")[1];
        // Split again to isolate the part before " - CODES : "
        String vinSection = postVin.split(" - CODES : ")[0];
        // Split into individual codes
        String[] codeArray = vinSection.trim().split("\\s+");
        
        for (String code : codeArray) {
            vinCodes.add(code);
        }
        
        // Output the result
        System.out.println("Extracted VIN Codes: " + vinCodes);
    }
}

Key Notes: #

• Both methods work regardless of what the actual VIN codes are—they only depend on the fixed VIN : and - CODES : markers.
• Using trim() and splitting on \\s+ (one or more spaces) handles any extra spaces that might appear in the input.
• If you're using a different language (like Python, C#, etc.), the core logic stays the same: locate the markers, extract the middle section, split into individual elements, and add to a list.

内容的提问来源于stack exchange，提问作者Radek Jackowiak